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Math question, I need help?
¤Solve by distrubitating(bad spelling)¤
{2x + 6y=-8}
{-x + 8y=3}
4 Answers
- 7 years ago
1) You need to get either the Xs or the Ys to cancel each other out. To do this, they need to have same coefficient. Pick the one that has smallest LCM (least common multiple). LCM of the Xs is 2, LCM of the Ys is 24. So for Xs, we want both Xs to have coefficient of 2. The top is already there so we dont need to do anything. The bottom we need to multiply by 2
2) When we multiple the x by 2, we also have to multiple the rest of the equation by 2.
Distribute: 2(-x+8y=3)
3) So now we have 2x + 6y=-8 and -2x +16y = 6.
4. since one x is negative and one is positive, adding together cancels out. SO add both equations together. Result for Ys is 16y + 6y = 22y. and -8 + 6 = -2.
5. Our equation now is 22y = -2 ----> y = -11, x = 91
- 7 years ago
I'm assuming you teacher wants you to distribute the 2 out of the first equation so:
2 (x+3y) = - 8
then, buy division,
x + 3y = - 4
and so, you can solve for your equation:
x + 3y = - 4
- x + 8y = 3
-------------------
11y = - 1
y = -1/11
and solve for x:
x + (3)(-1/11) = -4
x = -44/11 - -3/11 = -47/11
so, x = -47/11 and y = -1/11
- hayharbrLv 77 years ago
I never heard of that way but you could do it by elimination: divide the first equation by 2 then add the answer to the second
x + 3y = -4
-x + 8y = 3
--------------------
11y = -1 so y = -1/11 then plug that in to get x
x + 3(-1/11) = -4
x - 3/11 = -44/11
x = -41/11
- 7 years ago
Multiply the second equation by 2 (so basically ur distributing 2). After you do that now you can use the elimination method (add the equations together) to solve for y. After you solve for y, substitute ur answer for y in one of the two original equations to solve for x.