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? asked in Science & MathematicsBiology · 7 years ago

What is the Hardy-Wienberg Principle?

Nothing too long... brief but good please.

4 Answers

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  • Kevin
    Lv 6
    7 years ago

    In the Hardy-Weinberg formula, p + q = 1, where p is the frequency of one allele and q is the frequency of the other allele (often p is used as the frequency of the dominant allele and q is used as the frequency of the recessive allele). Since there are only two, then the total has to add to 1.

    If you square both sides of the above equation, you get:

    p^2 + 2pq + q^2 = 1, where p^2 is the frequency of homozygotes for one allele, 2pq is the frequency of heterozygotes and q^2 is the frequency of homozygotes for the other allele.

    So, if q^2 = 1/17000 = 0.0000588, then q = 0.00767

    so p = 1 - 0.00767 = 0.99233 (the frequency of the dominant allele). As an aside, note that the frequency of homozygous dominant individuals would be p^2 = 0.99233 * 0.99233 = 0.9847

    and finally,

  • Eric
    Lv 4
    7 years ago

    Given two forms of an allele, the Hardy-Weinberg formula (equilibrium) predicts the distribution of homozygous dominant, heterozgotes and homozygous recessive in a poulation. If the frequency of one allele is known, the distribution of the two possible homozygotes and the heterozygotes can be calculated by:

    A-squared + 2Aa + a-squared = 1.

  • ?
    Lv 7
    7 years ago

    Allele frequencies in a population will remain the same unless something is going on that's making them change. (Hardy and Weinberg were Captains Obvious.)

    http://en.wikipedia.org/wiki/Hardy%E2%80%93Weinber...

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