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Needing help with exponential function problems?
4^x * 2^(x^2)=16^2
3^(x^3)=9x
8^(-x+14)=16^x
e^x=e^(3x+8)
Yes it is 9^x. My apologies. Thanks
1 Answer
- BrainardLv 77 years ago
1 4^x * 2^(x^2)=16^2
(2^2)^x * 2^(x^2) = (2^4)^2............expressing 4 and 16 as powers of 2
2^(2x) * 2^(x^2) = 2^(8)
2^(2x + x^2) = 2^(8) ................ law of indices for multiplication
2x + x^2 = 8 ...............powers of the same base
x^2 + 2x - 8 = 0
(x + 4)(x - 2) = 0.................factorising
x = 2, - 4
2 3^(x^3)=9x ....... Is this suppose to be 3^(x^3) = 9^x?
3^(x^3) = (3^2)^x .........expressing 9 as powers of 3
3^(x^3) = 3^(2x)
x^3 = 2x
x^3 - 2x = 0
x ( x^2 - 2) = 0
x = 0, +/-sqrt(2)
3 8^(-x+14)=16^x
(2^3)^(-x + 14) = (2^4)^x ................ 8 = 2^3, 16 = 2^4
2^(-3x + 42) = 2^4x ................ power of power rule of exponents
- 3x + 42 = 4x ........................ If a^m = a^n, then m = n
42 = 7x
x = 6
4 e^x=e^(3x+8)
x = 3x + 8....................... If a^m = a^n, then m = n
- 2x = 8
x = - 4
Hope I made your day