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x^3 = 6x + 40. Solve for x?

1 Answer

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  • 7 years ago

    This is a polynomial. You need to complete the square, but since your x3 is on the opposite side, we need to follow the correct steps to bring it onto the correct side to follow the form of:

    x3 + x2 + x + Consonant = 0

    Start by subtracting x3 to both sides.

    x3 (-x3) = (-x3) + 6x + 40

    You will then have 0 on one side ( x3 - x3 = 0) and -x3 on the correct side of the equal sign. Second, we need to substitute our missing exponent.

    (-x3) + 0x2 + 6x + 40 = 0

    We can use 0 as our substitute. Start by factoring our cube.

    (x -/+ ?) (x -/+ ?) (x -/+?) = 0

    From here, you can solve for x in order to graph or find the value.

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