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Someone
Someone asked in Science & MathematicsPhysics · 6 years ago

physics electricity problem?

How much work is required to move a charge of 10 microcoulumbs a distance of 2.00m from a surface of 10V to a surface of -5.0V?

2 Answers

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  • ?
    6 years ago

    dV=10-(-5)=15V

    W=qdV=10*10^6*15=.15mJoule=150microjoule

  • oldschool
    Lv 7
    6 years ago

    The change in voltage = -5-10 = -15V = -15J/C and -15J/C * 10e-6C = -150e-6 J

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