How can i find the speed of something that has fallen 72 inches in.99 seconds 10 points for first answer?

+y = up

Vyi = initial velocity in the "y" or vertical direction

Vyғ = final velocity in the "y" or vertical direction

Hi = initial height = 6 ft

Hғ = final height = 0 (defined here)

g = -32.2 ft/sec

∆T = Tғ – Ti = 0.99 sec

∆h = Hғ – Hi

   Hғ{t}  =  (½) • g • t²  +  (Vyi) • t  +  Hi   ...   height versus time equation

        0  =  (½) • (-32.2) • (0.99)²  +  (Vyi) • (0.99)  +  6

       Vyi = 9.878 ft/sec

            Vyғ = (g • t)  +  Vyi   ...   velocity versus time equation

            Vyғ = (-32.2)(0.99) + 9.878

            Vyғ = -22 ft/sec

       The final speed is 22 ft/sec

distance = speed x time

therefore, speed = distance / time