Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

please help with physics problem! photo attached?

Attachment image

1 Answer

Relevance
  • 6 years ago

    kinetic energy gained = work done by the electric field (conservation of energy, 1st law of thermodynamics)

    this is the easiest way to model the problem.

    (*)Work done by the electric field = charge of proton x electric field strength x displacement

    = 1.602 x 10-19 C x 70000 x 0.2

    = 8.73 x 10^-16 J

    = 8.7 x 10^-16 J (2 significant figures)

    as described at the start, from conservation of energy, this is equal to the amount of kinetic energy gained by the proton.

    (*) this formula is obtained from Word done by an electric field = charge x change in potential difference

    in this case, change in potential difference = electric field strength x displacement.

    the displacement is quite easy to calculate as the displacement (0.2m) is in the same direction as the electric field (and the field direction shows the path a positive charge is influence, and the proton is positively charged), so we don't need to change signs.

Still have questions? Get your answers by asking now.