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Physics Question. Please help!?
In order to win the game, a placekicker must make a field goal from a distance of 42.0 m. The regulation height for the crossbar is 2.44 m. The placekicker decides to kick the ball with a speed of 24.2 m/s at an angle of 54.8° with respect to the horizontal.
a) Determine the amount by which the ball clears or falls short of clearing the crossbar. Enter a negative value if the ball falls short.
b) Determine if the ball is rising or falling as it approaches the crossbar.
1 Answer
- Richie AlfredLv 76 years agoFavorite Answer
horizontal speed of ball is constant = 24.2cos54.8° = 13.95 m/s
initial vertical speed = 24.2sin54.8° = 19.77 m/s
time taken to cover a horizontal distance of 42 m = distance / speed
= 42/13.95 = 3.01 s
in t = 3.01 s, v = u + at
vertical velocity = -19.77 + 9.81(3.01) = 9.75 m/s (downwards)
height = s = vₐᵥₑt = [19.77 - 9.75]3.01/2 = 15.08 m
therefore ball clears with (15.08 - 2.44) 12.64 m to spare
since the vertical velocity = 9.75 m/s (downwards) it is while falling
hope this helps
