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Physics question?
What is the magnitude of the centripetal acceleration of an object on the surface of the Earth at a latitude of 73.0°? Consider the Earth to be a sphere of radius R = 6.38 ✕ 10^6 m.
2 Answers
- ?Lv 76 years agoFavorite Answer
centripetal acceleration 'ac' is
ac = ω²r
ac = [(2π rad / 24hr) / (3600 s/hr)]² * 6.38(10^6)cos73.0
ac = 9.86(10^-3) m/s²
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- Anonymous6 years ago
This is not a simple question. Here is a simple explanation of what's involved: https://www.youtube.com/watch?v=q65O3qA0-n4