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? asked in Science & MathematicsMathematics · 6 years ago

Math Question!!!?

Find three consecutive integers such that the product of the first and third is 23 more than 10 times the second.

A. write a variable expression to represent the numbers.

B. Write an equation to solve the problem (turn the words into an equation using the variables in part A.)

C. solve the equation and find the numbers

2 Answers

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  • ?
    6 years ago

    B. n(n+2) = 10(n+1) + 23

    C. n^2 + 2n = 10n + 33

    n^2 - 8n - 33 = 0

    (n-11)(n+3) = 0

    n = 11 or -3

    First Set of numbers: 11, 12, 13 (this is correct)

    Second Set: -3, -2, -1 (which does not work)

  • hayharbr
    Lv 7
    6 years ago

    n = the first integer

    n + 1 = the second

    n + 2 = the third

    n(n + 2) = 10(n + 1) + 23

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