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C asked in Science & MathematicsChemistry · 5 years ago

Chemistry question... I am stuck on this... I don't know if I set it up right... PLEASE HELP?

How many mL of a 0.240 M HCL solution would be required to completely react with one solid tablet of regular-strength Tums, if each tablet contained 500.0 mg of CaCO3 according to the manufacturer?

I thought I needed to start by working to create a balanced equation?

1 Answer

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  • Roger the Mole
    Lv 7
    5 years ago

    2 HCl + CaCO3 → CaCl2 + CO2 + H2O

    (0.5000 g CaCO3) / (100.0875 g CaCO3/mol) x (2 mol HCl / 1 mol CaCO3) / (0.240 mol/L HCl) = 0.0416 L =

    41.6 mL HCl

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