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An electron is accelerated by a uniform electric field (1400 V/m ) pointing vertically upward?
use Newton's laws to determine the value of electron's velocity after it moves 0.50 cm from rest.
m/s
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- ?Lv 64 years agoFavorite Answer
a = Eq/m
a = (1400)*(1.6*10^-19) / (9.1*10^-31)
a = 2.46*10^14 m/s^2
v = sqrt(2aS)
v = sqrt(2*2.46*10^14*0.5*10^-2)
v = 1.568*10^6 m/s
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