CAN SOMEONE PLEASE FIND THE PH LEVELS FOR THESE 5 CHEM PROBLEMS!!!!!?

These are all strong acids or strong bases. As such, they completely ionize in solution. So:

1. 0.01 M HCl When this completely ionizes, [H+] = 0.01 M (Are you OK with that?) So,

pH = -log [H+] = - log 0.01 = 2.0

2. 0.0010 M NaOH

Here, [OH-] = 0.0010 M

You can get to pH two different ways.

(a) In any aqueous solution, [H+] X [OH-] = 1.00X10^-14

So, [H+] = 1.00X10^-14 / 0.0010 = 1.0X10^-11

pH = -log (1X10^-11) = 11.00

(b) Calculate pOH as pOH = -log [OH-]. So

pOH = -log (0.0010) = 3.00

pH + pOH = 14.00

pH = 14.00 - 3.00 = 11.00

3. 0.050 M Ca(OH)2

This is done the same was as 2., except that [OH-] = 2(0.050 M) = 0.10 M OH-. From here, follow #2.

4. 0.030 M HBr (Just like #1)

5. 0.150 M KOH (Just like #2)