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Maths help ples?
y = 16 x 10^8k
Find an expression, in terms of k, for y^5/4
Give your answer in standard form
3 Answers
- ComoLv 73 years ago
Will assume that you mean
y = 16 x 10^(8k)
y^(5/4) = [ 16 x 10^(8k) ]^(5/4)
y^(5/4) = 32 x 10^(10k)
y^(5/40 = 3•2 x 10^(10k + 1)
- mizooLv 73 years ago
y^(5/4) = (16 * 10^8k)^(5/4)
y^(5/4) = 16^(5/4) * (10^(8k))^(5/4)
y^(5/4) = (2^4)^(5/4) * 10^(8k * 5/4)
y^(5/4) = 2^5 * 10^(10k)
y^(5/4) = 32 * 10^(10k)
y^(5/4) = 3.2 * 10^(10k+1)
- billrussell42Lv 73 years ago
y^5/4 = (6 x 10^8k)^5/4
= 6^(5/4) x (10^8k)^5/4
= 6^(5/4) x 10^(8k•5/4)
= 6^(5/4) x 10^(10k)