vedere allegato?

1) the Fg force of mutual attraction between mass and earth.

F = GMm/r²

F = (6.674 x 10^-11)(5.972 × 10^24)(100) / (6.371 x 10^6 + 78000)²

F = 958.34...

F = 960 N

rounded to the two significant digits of the question numerals

2) the acceleration of the earth due to this force.

F = ma

a = F/m

a = 958.34 / 5.972 × 10^24

a = 1.6 x 10^-25 m/s²

which is a very very small acceleration.

If my translation and interpretation of this question is incorrect and it is really asking for the acceleration of the mass due to the earth, then

a = 958.34 / 100

a = 9.6 m/s²

3) the initial velocity Vo with which the object must be fired (frictions excluded)

ac = (Vo)²/r

Vo² = ac(r)

Vo² = 9.58(6.371 x 10^6 + 78000)

Vo² = 61803346.6

Vo = 7861.51...

Vo = 7900 m/s

or

Vo = √(GM/r)

Vo = √((6.674 x 10^-11)(5.972 × 10^24) / (6.371 x 10^6 + 78000))

Vo = 7861.52...

Vo = 7900 m/s

I hope this helps.

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perché l'utente Giorgio segnala a manetta basta vedere che solo lui è in testa alla classifica con 5,464 è penoso sta qui da solo ad autovotarsi, segnalatelo fino al ban, passate parola