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vedere allegato?

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2 Answers

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  • Whome
    Lv 7
    3 years ago
    Favorite Answer

    1) the Fg force of mutual attraction between mass and earth.

    F = GMm/r²

    F = (6.674 x 10^-11)(5.972 × 10^24)(100) / (6.371 x 10^6 + 78000)²

    F = 958.34...

    F = 960 N

    rounded to the two significant digits of the question numerals

    2) the acceleration of the earth due to this force.

    F = ma

    a = F/m

    a = 958.34 / 5.972 × 10^24

    a = 1.6 x 10^-25 m/s²

    which is a very very small acceleration.

    If my translation and interpretation of this question is incorrect and it is really asking for the acceleration of the mass due to the earth, then

    a = 958.34 / 100

    a = 9.6 m/s²

    3) the initial velocity Vo with which the object must be fired (frictions excluded)

    ac = (Vo)²/r

    Vo² = ac(r)

    Vo² = 9.58(6.371 x 10^6 + 78000)

    Vo² = 61803346.6

    Vo = 7861.51...

    Vo = 7900 m/s

    or

    Vo = √(GM/r)

    Vo = √((6.674 x 10^-11)(5.972 × 10^24) / (6.371 x 10^6 + 78000))

    Vo = 7861.52...

    Vo = 7900 m/s

    I hope this helps.

    Please remember to vote a Best Answer from among your results. It's good karma as it helps keep the exchange in balance.

  • Anonymous
    3 years ago

    perché l'utente Giorgio segnala a manetta basta vedere che solo lui è in testa alla classifica con 5,464 è penoso sta qui da solo ad autovotarsi, segnalatelo fino al ban, passate parola

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