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chemistry question?
A 0.113 g sample of a gas exerts a pressure of 780 torr in a 50.4 mL container at 23◦C. What is the molar mass of this gas?
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- Roger the MoleLv 72 years agoFavorite Answer
n / V = P / RT = (780 torr) / ((62.36367 L torr/K mol) x (23 + 273) K) = 0.0422543 mol/L
(0.113 g) / (0.0504 L) / (0.0422543 mol/L) = 53.1 g/mol
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