Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

? asked in Science & MathematicsMathematics · 2 years ago

law of cosines?

how to find measure of angle B when angle A=84, side c is 16 and side b is 17? i have a test on this in an hour and i still don’t know how to do it PLEASE HELP

3 Answers

Relevance
  • 2 years ago
    Favorite Answer

    Law of cosines equation is:

    c² = a² + b² - 2ab cos(C)

    Where the length "c" is opposite of angle "C".

    You are given angle "A" and do not have length "a", so we can rearrange the variables to be:

    a² = b² + c² - 2bc cos(A)

    Now we can substitute what we know and solve for "a":

    a² = 17² + 16² - 2(17)(16) cos(84)

    a² = 289 + 256 - 544 cos(84)

    a² = 545 - 544 cos(84)

    a² = 545 - 544(0.1045285)

    I rounded here, but didn't in my calculator to reduce errors due to rounding:

    a² = 545 - 56.86348

    a² = 488.136516

    a = 22.093812

    I'll keep things to 5 or 6 DP to try to limit rounding errors until the end.

    Now that we know the length of "a", we can use law of sines with angle "A" and length "b" to solve for angle "B":

    22.093812/sin(84) = 17/sin(B)

    22.093812 sin(B) = 17 sin(84)

    sin(B) = 17 sin(84) / 22.093812

    Again, decimal approximation, but not rounded in my calculator:

    sin(B) = 17(0.994522) / 22.093812

    sin(B) = 16.906872 / 22.093812

    sin(B) = 0.765231

    Inverse sine function to get:

    B = 49.928° (rounded to 3DP)

  • 2 years ago

    law of cosines relates the lengths of the sides of a plane triangle to the cosine of one of its angles. If a, b, c are the three sides of a triangle, and C is the angle between a and b and opposite side c, then:

    c² = a² + b² – 2abcosC

    or cos C = (a² + b² – c²) / (2ab)

    cos A = (b² + c² – a²) / (2bc)

    cos B = (a² + c² – b²) / (2ac)

    A = 84º

    c = 16

    b = 17

    rearrange the formula so you can get a

    cos A = (b² + c² – a²) / (2bc)

    b² + c² – a² = (2bc) cos A

    a² = b² + c² – (2bc) cos A

    a² = 17² + 16² – (2•17•16) cos 84

    a² = 289 + 256 – 56.86

    a = 22.09

    cos B = (a² + c² – b²) / (2ac)

    cos B = (22.09² + 16² – 17²) / (2•22.09•16)

    cos B = (487.97 + 256 – 289) / (706.88) = 0.6436

    B = 49.9º

  • 2 years ago

    The cosine of an angle is the ratio between one side and the other side.

    So if you have a triangle where the base is 17 and the hypotenuse is 16, the cosine of the angle is 16/17, or 0.9412 (rounded to 4 places).

    So your job is to find the angle whose cosine is 0.9412. My trig calculator is at work but you could figure that out. I get 19.7459 degrees.

Still have questions? Get your answers by asking now.