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law of cosines?
how to find measure of angle B when angle A=84, side c is 16 and side b is 17? i have a test on this in an hour and i still don’t know how to do it PLEASE HELP
3 Answers
- llafferLv 72 years agoFavorite Answer
Law of cosines equation is:
c² = a² + b² - 2ab cos(C)
Where the length "c" is opposite of angle "C".
You are given angle "A" and do not have length "a", so we can rearrange the variables to be:
a² = b² + c² - 2bc cos(A)
Now we can substitute what we know and solve for "a":
a² = 17² + 16² - 2(17)(16) cos(84)
a² = 289 + 256 - 544 cos(84)
a² = 545 - 544 cos(84)
a² = 545 - 544(0.1045285)
I rounded here, but didn't in my calculator to reduce errors due to rounding:
a² = 545 - 56.86348
a² = 488.136516
a = 22.093812
I'll keep things to 5 or 6 DP to try to limit rounding errors until the end.
Now that we know the length of "a", we can use law of sines with angle "A" and length "b" to solve for angle "B":
22.093812/sin(84) = 17/sin(B)
22.093812 sin(B) = 17 sin(84)
sin(B) = 17 sin(84) / 22.093812
Again, decimal approximation, but not rounded in my calculator:
sin(B) = 17(0.994522) / 22.093812
sin(B) = 16.906872 / 22.093812
sin(B) = 0.765231
Inverse sine function to get:
B = 49.928° (rounded to 3DP)
- billrussell42Lv 72 years ago
law of cosines relates the lengths of the sides of a plane triangle to the cosine of one of its angles. If a, b, c are the three sides of a triangle, and C is the angle between a and b and opposite side c, then:
c² = a² + b² – 2abcosC
or cos C = (a² + b² – c²) / (2ab)
cos A = (b² + c² – a²) / (2bc)
cos B = (a² + c² – b²) / (2ac)
A = 84º
c = 16
b = 17
rearrange the formula so you can get a
cos A = (b² + c² – a²) / (2bc)
b² + c² – a² = (2bc) cos A
a² = b² + c² – (2bc) cos A
a² = 17² + 16² – (2•17•16) cos 84
a² = 289 + 256 – 56.86
a = 22.09
cos B = (a² + c² – b²) / (2ac)
cos B = (22.09² + 16² – 17²) / (2•22.09•16)
cos B = (487.97 + 256 – 289) / (706.88) = 0.6436
B = 49.9º
- Mr. SmartypantsLv 72 years ago
The cosine of an angle is the ratio between one side and the other side.
So if you have a triangle where the base is 17 and the hypotenuse is 16, the cosine of the angle is 16/17, or 0.9412 (rounded to 4 places).
So your job is to find the angle whose cosine is 0.9412. My trig calculator is at work but you could figure that out. I get 19.7459 degrees.