Calculate the energy involved when 35 grams of ice at -3 degrees is heated to gaseous water at 102 degrees?

here is a similar Q/A, just change a few numbers.

Question: What is the energy needed to heat 1 kg of ice at –20ºC to steam at 150ºC

Ans:

specific heat of water is 4.186 kJ/kgC

specific heat of ice is 2.06 kJ/kgC

specific heat of steam is 2.1 kJ/kgK

heat of fusion of ice is 334 kJ/kg

heat of vaporization of water is 2256 kJ/kg

5 parts to this problem, add them up to get the total

to warm ice to 0ºC

E₁ = 2.06 kJ/kgC x 1 kg x 20ºC

to melt ice

E₂ = 334 kJ/kg x 1 kg

to warm water from 0ºC to 100ºC

E₃ = 4.186 kJ/kgC x 1 kg x 100ºC

to boil water

E₄ = 2256 kJ/kg x 1 kg

to heat steam from 100ºC to 150ºC

E₅ = 2.1 kJ/kgC x 1 kg x (150–100)ºC

E = E₁ + E₂ + E₃ + E₄ + E₅