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The specific heat of gold is 0.129 J/g^oC} If a 32.76 g sample of gold at 35 oC is heated to 84 oC,?
how many joules of energy were absorbed?
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- 2 years agoFavorite Answer
Q = m * c * dT
m = 32.76 g
dT = 84 - 35 = 49 C
c = 0.129 J/(g * C)
Q = 32.76 * 49 * 0.129 Joules
Q = 207.07596
Q = 207.1 Joules
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