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Combustion analysis of an unknown compound containing only carbon and hydrogen produced 2.277 g of CO2 and 1.161 g of H2O. Empiric. formula?
1 Answer
- ?Lv 72 years agoFavorite Answer
moles of CO2 = 2.277 g / 44 g/mole = 0.05175 moles
there is 1 mole of C in CO2 so we have 0.05175 moles of C in the compound
moles of H2O = 1.161 g / 18 g/ mole = 0.0645 moles of H2O
moles of H in the compound = 0.129 mol because we have 2 moles of H in H2O
molar ratio C:H in the compound = 0.05175 :0.129
divide by the smaller number to simplify the ratio and we have 1:2.5
to get integer numbers we multiply by 2 and we get
C:H - 2:5
empirical formula is C2H5.. an alkene
