A compound is isolated from the rind of lemons that is found to be 88.14% carbon and 11.86% hydrogen by mass. How many moles of C and H?

(120 g) (0.8814) = 105.768 g of C in the 120 g of the CH compound

120 minus 105.768 = 14.232 g of H in the 120 g of CH cmpd

105.768 g / 12.011 g/mol = 8.806 mol of C in the 120 g

14.232 g / 1.008 g/mol = 14.12 mol of H in the 120 g

The answer by Bobby_Thin used 100 g, not the 120 in your question.

8.81 moles of C. 14.1 moles H.

in 100 g of compound we have 88.14 g of C or 88.14 / 12 mol of C = 7.345 mol of C

mole of H in that mass = 11.86 / 1.00 = 11.86 mol of H

You might want to move this question to the chemistry section. And finish asking it.

(probably involves comparing the mass-per-mole of carbon vs hydrogen)