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Physics help?
the popular show, The wheel of Fortune, a contestant gives the wheel an initial angular
velocity of -5.95 rad/s and the wheel stops after 5.8s of constant acceleration. Determine
the panel (e.g. $600 or bankrupt) that the yellow pointer will be on when the wheel stops
1 Answer
- FiremanLv 71 year ago
By ω2 = ω1 + αt
=>0 = -5.95 + α x 5.8
=>α = 1.19 rad/sec^2Now by ω2^2 = ω1^2 + 2αθ =>0 = (-5.95)^2 + 2 x 1.19 x θ=>θ = -14.87 rad {-ve just indication that the displacement is against the acting force}Now as 1 rad = 180/π=>14.87 rad = (180 x 14.87)/3.14 = 852.71*For yellow pointer to be on the mark 852.71 shall be a nth integer of 360*=>852.71/360 = 2.37=> Not on mark