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What is the temperature, in °C, of 0.54 mol of gas at a pressure of 1.2 atm and a volume of 12.3 L?
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- hcbiochemLv 71 year ago
PV = n RT
(1.2 atm) (12.3 L) = 0.54 mol (0.08206 Latm/molK) (T)
T = 333 K - 273 = 60.C
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