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? asked in Science & MathematicsChemistry · 1 year ago

A current of 4.60 A is passed through a Ni(NO3)2 solution for 1.90 h. How much nickel is plated out of the solution?

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  • Roger the Mole
    Lv 7
    1 year ago
    Favorite Answer

    Ni{2+} + 2 e{-} → Ni

    (4.60 A) x (1.90 h x 3600 sec/h) / (96485.3399 C/mol e{-}) x (1 mol Ni / 2 mol e{-}) x

    (58.6934 g Ni/mol) = 9.57 g Ni

  • Anonymous
    1 year ago

    amps * time in seconds = coulombs.  Coulombs / 96500 = moles of electrons.  Moles of Ni = 1/2 * moles of electrons.

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