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Whats the molarity of an oxalic acid H2C2O4(aq) if a 10.00mL sample of that acid requires 25.80mL of 0.1573M NaOH to neutralize in titration?
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- hcbiochemLv 71 year ago
H2C2O4(aq) + 2 NaOH(aq) --> Na2C2O4(aq) + 2 H2O
Moles NaOH used = 0.02580 L X 0.1573 mol/L = 4.058X10^-3 mol NaOH
Moles oxalic acid = 4.058X10^-3 mol NaOH X (1 mol H2C2O4 / 2 mol NaOH = 2.029X10^-3 mol H2C2O4
Molarity H2C2O4 = 2.029X10^-3 mol / 0.01000 L = 0.2029 mol/L H2C2O4
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