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evaluate the following trig expression sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)?
show work please
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- Wayne DeguManLv 712 months agoFavorite Answer
sin(A - B) => sinAcosB - cosAsinB
so, sin(5π/6 - 3π/8) => sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)
i.e. sin(11π/24) = 0.991...to 3 s.f.
:)>
- sepiaLv 712 months ago
sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)
= 1/2 sqrt(2 + sqrt(2 + sqrt(3)))
= 0.991444861373810411144557526928562871277738274448102271458...
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