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evaluate the following trig expression sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)?

show work please

2 Answers

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  • 12 months ago
    Favorite Answer

    sin(A - B) => sinAcosB - cosAsinB

    so, sin(5π/6 - 3π/8) => sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)

    i.e. sin(11π/24) = 0.991...to 3 s.f.

    :)>

  • sepia
    Lv 7
    12 months ago

    sin(5π/6)cos(3π/8) - cos(5π/6)sin(3π/8)

    = 1/2 sqrt(2 + sqrt(2 + sqrt(3)))

    = 0.991444861373810411144557526928562871277738274448102271458...

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