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nico asked in Science & MathematicsPhysics · 12 months ago

what is the ratio of magnitude of centripetal accel. to accel. due to gravity? of. a wheel w/ 7.5 cm and rotates at 6500 rev/min?

An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 6500 rev/min

The ratio of magnitude of centripetal acceleration to acceleration due to gravity is

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  • oubaas
    Lv 7
    12 months ago

    Ca = ω^2*r = (0,10472*6500)^2*7.5/100 =  34,750 m/sec^2 

    Ca/g = 34,750 / 9.807 = 3,540 

  • 12 months ago

    ω = 6500rev/min * 2π rad/rev * 1min/60s = 13,000π/60 = 650π/3 = 681rad/s

    V = ωr -----> V²/r = ω²r = 34,750

    34750/9.8 = 3546

  • 12 months ago

    a/g = w^2 R / g = (2*pi() * 6500/60)^2 * 0.075 / 9.8  ~= 3.5 * 10^3

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