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Calculate how much energy is required to heat 50 g of mercury from −50oC to 750oC.
Hfus = 2.33 kJ/molc(solid) = 0.141 J/goCc(gas) = 0.104 J/goCboiling point = 357oCHvap = 58.6 kJ/molc(liquid )= 0.138 J/goCmelting point = −39.0oCMM (Hg) = 200.59 g/mol
1 Answer
- Roger the MoleLv 711 months ago
(50 g) / (200.59 g/mol) = 0.24926 mol
(0.138 J/g°C) x (50 g) x (−39.0 − (−50))°C =
75.9 J to warm the solid to its melting point
(2.33 kJ/mol) x (0.24926 mol) = 0.5808 kJ to melt the solid
(0.138 J/g°C) x (50 g) x (357 − (−39.0))°C =
2732.4 J to heat the liquid to its boiling point
(58.6 kJ/mol) x (0.24926 mol) = 14.6066 kJ to vaporize the liquid
(0.104 J/g°C) x (50 g) x (750 - 357)°C = 2043.6 J to heat the vapor to 750°C
0.0759 kJ + 0.5808 kJ + 2.7324 kJ + 14.6066 kJ + 2.0436 kJ = 20.0 kJ total
