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1 Answer
- jacob sLv 711 months ago
Static Equilibrium:
∑ Fx = 0
∑ Fy = 0
∑ FM = 0
So,
∑ Fx = 0 ⇒ F1 cos 60° + 6- F3-10 cos 45°+ F2 cos 60° = 0
⇒ F1 + F2 + 12 -2F3 -20/√2 =0
∑ Fy = 0 ⇒ F1 sin 60° + 12 -10 sin 45°- F2 sin 30°= 0
⇒ √2 F1 + 24 - 20/√2 - √3 F2 =0
∑ FM = 0 ⇒ 6 x 4 + 20 + 10 x 2 cos 45° + F2 x 4 sin 60° = 0
⇒ 24 + 20 + 20/√2 + √3 F2 =0
solving then, we get :
⟦F1⟧ = 22.45 KN
⟦F2⟧ = 16.78 KN
⟦F3⟧ = 20.7 KN
option (b) is correct
