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A roller coaster (425. kg) moves from A (5.00 m above the ground) to B (18.0 m above the ground). Two nonconservative forces are presen?
A roller coaster (425. kg) moves from A (5.00 m above the ground) to B (18.0 m above the ground). Two nonconservative forces are present: friction does -2.00 x10^4 J of work on the car, and a chain mechanism does +3.00 x 10^4 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ΔKE = KEf - KE0, from A to B?
______J
1 Answer
- ?Lv 711 months agoFavorite Answer
ΔKE = 3.00E4J - 2.00E4J + (5.00 - 18)m * 425kg * 9.8m/s²
ΔKE = -4.41E4 J
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