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physics problem?
in 1992, a team of firefighters pumped 143 x 10^3 kg of water in less than four days. What a mass of wood can be cooled from a temperature of 280 C to one of 100 C using this amount of water? assume that the initial temperature of the water is 20 C and that all of the water as a final equilibrium temperature of 100 C, but that none of the water is vaporized. Use 1700 J/kg*C for the specific heat capacity of wood. (mixture)
answer-
1 Answer
- ?Lv 72 months agoFavorite Answer
heat gained by water = heat lost by wood
143E3kg * 4186J/kg·ºC * 80ºC = m * 1700J/kg·ºC * 180ºC
mass m = 1.56E5 kg = 156E3 kg