A gas sample with a volume of 5.3 L has a pressure of 745 mmHg at 29 ∘C.?

745 mmHg x (96 + 273) K / (29 + 273) K = 910 mmHg

PV=nRT <<<memorize!!

n is moles, R is gas constant (use correct one!), T is temp in K (C+273.15)

Since you have a before and after with the same n &R simplifies to

PV/T initial = nR = PV/T final

Now sub in your numbers and solve

SI Units R values:

8.31446261815324 J⋅K−1⋅mol−1

8.31446261815324 m3⋅Pa⋅K−1⋅mol−1

8.31446261815324 kg⋅m2·K−1⋅mol−1s−2

8.31446261815324×103 L⋅Pa⋅K−1⋅mol−1

8.31446261815324×10−2 L⋅bar⋅K−1⋅mol−1

0.082057 L atm mol-1K-1

62.36L·torr/mol·K = L·mmHg/mol·K

P1/T1 = P2/T2

745 / (29+273) = P2 / (96+273)

P2 = 910 mm Hg