Please help! Modern Physics Problem.?

Question

An astronaut in space travels in a spacecraft (a side view of spacecraft at rest on the ground is shown below). What is the speed when its area is exactly 1/2 of its rest area? 
If you go onto the spacecraft for 1 hour (measured by your phone that is with you) at the speed found, how long did the people on Earth wait for your return? Please help, I am very confused.

oldschool · Answer

The area of the spacecraft sideview = ½ * base * height = ½*55.8*18.9 = 527.31
To half that  ½*L'*18.9 = ½*527.31 = 263.655
L' = 2*263.655/18.9 = 27.9 = 55.8*√[1-(v/c)²]
√[1-(v/c)²] = 27.9/55.8
1-(v/c)² = (27.9/55.8)² = 0.25
(v/c)² = 1 - (27.9/55.8)² = 0.75
t = to/√(1-0.75²) = 1/√(1-0.75²) = 1.51hr

billrussell42 · Answer

did you list the question exactly as given? because it makes little sense as is.

"go onto the spacecraft for 1 hour" ?? what does this mean?

I suspect this is about relativistic motion ?

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Please help! Modern Physics Problem.?

2 Answers