The sides of a triangle are in the ratio of 1/2:1/3:1/4. If the perimeter is 52 cm, the length or the smallest side is?

I'd first multiply all the fractions by the LCD of 12 to get rid of denominators.

12*½ : 12*⅓ : 12*¼

= 6 : 4 : 3

Now think of the sides as 6k, 4k and 3k respectively. These add up to 52 cm.

6k + 4k + 3k = 52

13k = 52

k = 4

The sides are therefore:

6k → 6(4) = 24 cm

4k → 4(4) = 16 cm

3k → 3(4) = 12 cm

Note: We could have kept the numbers as fractions and you could have still gotten the same answer.

Let the sides be ½x, ⅓x and ¼x respectively.

½x + ⅓x + ¼x = 52

(½ + ⅓ + ¼)x = 52

(6/12 + 4/12 + 3/12)x = 52

(13/12)x = 52

x = 52*(12/13)

x = 52/13 * 12

x = 4*12

x = 48

So the sides are:

½x → 48/2 = 24 cm

⅓x → 48/3 = 16 cm

¼x → 48/4 = 12 cm

I just like working with integers rather than fractions which is why I multiplied it all by 12 at the beginning.

Answer:

The shortest side is 12 cm

1/2x + 1/3x + 1/4x = 52

13/12x = 52

x = 48

1/2x = 1/2(48) = 24

1/3x = 1/3(48) = 16

1/4x = 1/4(48) = 12

Therefore the length of the smallest side is 12 cm..

The length of the smallest side=

(1/4)52/(1/2+1/3+1/4) cm=

13/[(6+4+3)/12] cm=

12 cm

 The sides of a triangle are in the ratio of 1/2 : 1/3 : 1/4. 

 1/2 : 1/3 : 1/4 = 6 : 4 : 3

  If the perimeter is 52 cm, 

  the length or the smallest side is 12 cm.

The 3 sides are: a, b, c

a / b / c = (1/2) / (1/3) / (1/4)

a / b = (1/2) / (1/3) → a/b = 3/2 → a = 3b/2

b / c = (1/3) / (1/4) → b/c = 4/3 → c/b = 3/4 → c = 3b/4

The perimeter is 52:

a + b + c = 52

(3b/2) + b + (3b/4) = 52 → you multiply by 4 both sides

6b + 4b + 3b = 208

13b = 208

→ b = 16

Recall: a = 3b/2

→ a = 24

Recall: c = 3b/4

→ a = 12

The 3 sides are: 12 ; 16 ; 24 and the smallest one is 12

6/12, 4/12, 3/12

6+4+3= 13

52/13= 4

4*6= 24, 4*4= 16, 4*3= 12 cm

Multiply ratios 1/2:1/3:1/4 by 12 and you get 6:4:3

The length or the smallest side is (3/13)*52 = 12