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- Jeff AaronLv 73 weeks ago
(a)
Let u = 5x^(-1), so da/dx = -5x^(-2)Let y = arccos(5/x) = arccos(u), so:dy/du = -1 / sqrt(1 - u^2)dy/du = -1 / sqrt(1 - (5x^(-1))^2)dy/du = -1 / sqrt(1 - 25x^(-2))By the Chain Rule:
dy/dx = dy/du * du/dx
dy/dx = (-1 / sqrt(1 - 25x^(-2))) * (-5x^(-2))
dy/dx = 5 / (x^2*sqrt(1 - 25x^(-2)))
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