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How much heat is required to vaporize 50.6 g of acetone at its boiling point? ?
The heat of vaporization of acetone at its boiling point is 29.1 kJ/mol.
Express your answer in kilojoules to three significant figures.
1 Answer
- Uncle MichaelLv 72 weeks ago
Molar mass of acetone (CH3COCH₃) = (12.0×3 + 1.0×6 + 16.0) g/mol = 58.0 g/mol
Moles of acetone vaporized = (50.6 g) / (58.0 g/mol) = 0.872 mol
Heat required = (0.872 mol) × (29.1 kJ/mol) = 25.4 kJ
====
OR:
(50.6 g acetone) × (1 mol acetone / 58.0 g acetone) × (29.1 kJ of heat / 1 mol acetone)
= 25.4 kJ of heat
