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Math question?
A bank teller has 51 $20 and $5 in her cash drawer.the value of the bills is $510. How many $20 are there?
3 Answers
- MichaelLv 72 weeks ago
f = number of $5 bills
t = number of $20 bills
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A bank teller has 51 $20 and $5
f + t = 51
Multiply both sides by 5
5f + 5t = 255 Eq 1
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value of the bills is $510
5f + 20t = 510 Eq 2
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Subtract Eq 1 from Eq 2
5f + 20t = 510
- (5f + 5t = 255)
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15t = 255
Divide both sides by 15
t = 17 <–––––––
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- Ray JLv 72 weeks ago
Make X the number of $20 bills.
Therefor 51-X is the number of $5 bills.
20X + 5(51-X) = 510
20X + 255 - 5X = 510
15X + 255 = 510
15X = 510 - 255
15X = 255
X = 17
17 $20 bills