Michael Grewal

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(a) Find the current flowing through each resistor.

I've found the ones for the 2.5 resistors (obviously 3.6 A). i need help on how to solve the 6.3 resistor most importantly and I think I can get moving with this problem. I don't understand what I am doing wrong, please explain how and which resistances are added for my Req.

Really confused, please help, Thanks in advance. I'll definitely rate.

A uniform electric field with a magnitude of 1400 N/C points in the negative x-direction, as shown in the figure below. A particle with a mass of 3.5 g and a charge of 0.055 µC is released from rest at point A.

(b) What speed will it have after moving through a distance of 5.0 cm? The electric field has a magnitude of 1400 N/c.

make sure to answer it in cm/s, but m/s would work too

I kept getting numbers like 2 and 18 cm/s.

What I did:

I found work done by first solving force by saying W=Fe/q

Fe=7.7E-5

W=(.05)(Fe)=3.85E-6

What I tried: made my kinetic energy equal to work and solved W=(1/2)mv^2, didn't work

Tried energy conservation, where initial kinetic energy and potential energy equal zero

Tried making Ve=Ey and also Ve=kQ/r equations plugged into the potential energy line, Ue=kQ^2/r.

I think this is right but might be making calculation errors or a mistake in my energy conservation line. Please help!

A uniform electric field with a magnitude of 1400 N/C points in the negative x-direction, as shown in the figure below. A particle with a mass of 3.5 g and a charge of 0.055 µC is released from rest at point A.

(b) What speed will it have after moving through a distance of 5.0 cm? The electric field has a magnitude of 1400 N/c.

make sure to answer it in cm/s, but m/s would work too

I kept getting numbers like 2 and 18 cm/s.

What I did:

I found work done by first solving force by saying W=Fe/q

Fe=7.7E-5

W=(.05)(Fe)=3.85E-6

What I tried: made my kinetic energy equal to work and solved W=(1/2)mv^2, didn't work

Tried energy conservation, where initial kinetic energy and potential energy equal zero

Tried making Ve=Ey and also Ve=kQ/r equations plugged into the potential energy line, Ue=kQ^2/r.

I think this is right but might be making calculation errors or a mistake in my energy conservation line. Please help!

Let q = +1.2 µC and d = 39 cm.

Find the direction of (from the x-axis, which points to the right) and magnitude.

The direction is screwing me up! What would that be in degrees??

I used 45 degrees and got the correct magnitude - ~0.75 N and it says the direction for 45 degrees is incorrect. Confused...please help

Physics Question!

I am confused at how we get the answer. I've tryed to solve for a quadratic but its not working out. steps would be very helpful. Thanks!