sendona

Recently I added a microsoft account to my Windows 10 and removed it later. I'm not sure if I've changed any other option or not, but the lock screen page does not show up after I wake my laptop from sleep mode. That is, the laptop goes into the Windows environment directly with no lock screen page at first. So how can I get the lock screen back after Waking windows from sleep?

Are the internet connections with 1MB speed and above suitable for watching online TVs? By suitable I mean without any pauses for buffering.

I need to find two positive sequence, c(n) and t(n), satisfying the conditions below:

1- The infinite series with general term

[(t(n))^2/(n*c(n))]*exp{ -B*[ (c(n))^2/( c(n)+n ) ] }

is convergent where 0<B<1,

2- t(n) → ∞, c(n) → 0 and t(n)*c(n) → ∞ as n → ∞.

3- lim ( c(n)/n^(-1/2) ) = 0 as n → ∞.

Thanks for any help!

I need to find some positive sequence, c(n), satisfying the conditions below:

1- The infinite series with general term

[1/(n*c(n))]*exp{ -B*[ (c(n))^2/( c(n)+n ) ] }

is convergent where 0<B<1,

2- lim ( c(n)/n^(-1/2) ) = 0 as n → ∞.

Thanks for any help!

There was a contact from hotmail in my Yahoo messenger contact list that just deleted it. I set to appear offline to that contact before deleting. Will I appear online to this contact every time singing into Yahoo messenger?

This is a problem I’ve been working on for long with no results. I hope someone from mathematics can help me. Maybe I couldn’t have found the answer because my major is statistics.

I’d like to find two sequences, say ε(n) and t(n), which satisfy the following conditions:

1- ε(n)/n^(-γ) tends to 0 when n → ∞, where 0<γ<1/2,

2- Both of t(n) and t(n)*ε(n) tend to ∞ when n → ∞,

3- The infinite series with the general term (t(n))^2/((ε(n))^2*n) is convergent.

Note: One suggestion is to take t(n) as (log(n))^a/ε(n) with a>0 so that t(n) tends to ∞; thus ε(n)*t(n) → ∞ easily follows. I’ve worked on this very much but have earned no results. So maybe another idea should be taken.

I know it’s a difficult problem and I don’t really expect anyone work on it and give me the final result. But I’d be thankful to receive any suggestions which I would work on and see if it works.

It's known that p-series, which are in the form of 1/n^p, are convergent when p>1. Is there any other convergent series, say a(n), which is greater than any convergent p-series? So that for example the convergence of all p-series can be proven by using the Limit Comparison Test and a(n)? It would be more of interest if a(n) includes logarithmic expressions.

I'd like to find the greatest value of y which satisfies the inequalities below regarding the mentioned conditions:

-2*y + p*y - p + 1 < 0,

-2*a - 2*b - p*b < 0,

where a>b>0, y>0 and 1<p<=2.

It's known that the series with general term 1/n*log(1+1/n) is convergent (according to the limit comparison test, in which the compared series is with the general term 1/n^2). Now I'm looking for some convergent series which includes a term n with a degree more than 0 and include a logarithmic term, too. In the example given, n is of the degree -1 which is negative, but I need a positive degree as said. Are there any series of this form at all?

Any help would be highly appreciated!

I have the following statement but have no idea how it's true:

O(1)*[n + n^(p/2)] <= O(1)*n^(p/2),

where O is the big O notation and n>=1 is an integer. I just don't get it why we can write n<=O(1) so that the second statement above is concluded.

What would be my approximate download/upload size used in 1 hour video chat if only the other side is sharing and I'm just watching? And also what would be it if I'm both sharing and watching video? I want to know the total download and upload size in these two cases while using Yahoo! messenger 11.0.0.1175 for video chat.

Would be the size meaningfully less if the sound is mute?

Thanks for any help in advance, I really need to know this information.

Problem:

Problem: Find the value of this limit:

L= lim x*[1/x], as x → 0, where [x] is the smallest integer number less than x (integral part of x).

Solution:

Let y = 1/x, then:

y → +∞ as x → 0+ (0+ means approaching from right side of 0),

y → -∞ as x → 0- (0- means approaching from left side of 0).

Now we have:

1)

L = lim 1/y*[y], as y → +∞

= lim (y+1)/y, as y → +∞ (*)

= 1.

2)

L = lim 1/y*[y], as y → -∞

= lim (y-1)/y, as y → -∞ (**)

= 1.

Since the values of (1) and (2) are equal, we conclude that the limit value exists and is 1𝑥

Now my question is about the parts highlighted by (*) and (**). I don't understand how we conclude them.

Thanks for any answers in advance.

We have:

e^(-x) > 1 - x ; for all 0<x<1.

I know that we can use it's Taylor expansion around the point x=0, which is:

e^(-x) = 1 - x + x^2/2 - x^3/3! + x^4/4! - ... .

The inequality can be concluded by subtraction the term (- x^3/3! + x^4/4! - ...) from the right side. To do this, we must have

- x^3/3! + x^4/4! - ... > 0

Now my question is that how we know the term (- x^3/3! + x^4/4! - ...) is positive?

I use the add

http://heartshare.bravehost.com/

to chat with my friends. Sometimes after logging in, the opened chat window gets stuck in the 'connecting' or 'authentication' step so the chat room does not appear. I know that it's not my connection speed, so it does not open even if I wait for a long time. Please help me to find what the problem is.

Note: I usually don't have such a problem and the chat window easily opens. But during the last two days this problem has persisted, and also had this problem several times before.

I use the latest version of Yahoo messenger (10.0.0.1270). I've checked the voice settings thorough:

messenger/preferences/Video & Voice/Open Video and Voice Setup

which shows my microphone works. Still the voice call button on the IM window is inactivated for the contacts support voice calls. How can have a voice chat with them?

Question: Construct one example of a joint density of the real scalar random variables X and Y which is not bivariate normal binomial but the conditional density of Y given X=x is normal with the expected value a linear function of x and the variance free of x.

My information: We know that if the joint density of X and Y is bivariate normal, the conditional density is normal too with given (it is proved before) expected value and variance. Here we aren't allowed to use a bivariate normal density for (X,Y). I do not need to know all the details of proves, I just need to know what the joint density of (X,Y) and marginal distributions of X and Y (or at least X) should be.

Thanks for your help.

Find the probability or density function for which the moment generating function, M(t), is:

M(t)=8*5^t/(2-t)^3

Let X and Y be two discrete random variables. Given

Pr[X = z], P[Y = z] and Pr[max(X,Y) = z],

find Pr[min(X , Y) = z].

Find u and l such that H=u-l is minimized over all l and u, with these conditions:

(i) 0 < l < u < 1,

(ii) (m^2 - l^2)/m + (2u – u^2 - 2m + m^2)/(1- m) = c where 0 < c <1 and 0 < m < 1 are known constants.