Vishal

This is written in my physical chemistry book and i dont seem to understand even a bit of it:

For any compound MxNy (x.y in subscript)

y X no. of moles of M = x X no. of moles of N (M,N are elements)

i feel like my time is being wasted when i go to school as the teachers are not really good and i cover everything in my coaching and tutions...... please mention all the pros and cons about open schooling for preparing for iit jee

thanks in advance

One end of a spring is attached to a wall and the other end is attached to a block of mass m. If i stretch the block to a distance x from the mean position, there will be a force equal to kx acting on the block towards the mean position. My question is that will an equal force act on the wall too ?

http://cnx.org/content/m14782/1.6/wp1.gif

confused about the free body diagram....

Masses : 1=3kg,2=2kg,3=0.6kg,4=4kg

Why is the total downward pull on pulley B not equal to the sum of weights of 3 and 4 ?

If i dont know the acceleration of the 2 pulleys(hence the masses), how am i supposed to calculate anything(such as tension) ?? Please help asap.....

if a spring balance is fixed to the roof..... and 2 forces P and Q are applied to the 2 ends what would be the reading ? The spring balance can not move

Now, if the coefficient of static friction is 0.4 and that of kinetic friction is 0.3, and if i apply a force on a box of 10 kg, the box won't move till the applied force is 40N (by the formula f=μ(s)N). But as soon as the force becomes more than 40, the box starts moving and kinetic friction comes into play. The value of kinetic friction is 30N so does that mean that if lower the force to a little more than 30N, the box would still remain in motion ?

would appreciate a detailed answer....