computeranswers

I understand that penta is 5 but if it is P2O5 shouldn't it be diPhosphorus Pentaoxide? I thought P was usually P4

I feel like this is wrong because how do you have 1.5Br2 I thought you could only have whole numbers, but the charges and atoms balance.

NO31-(aq) + Br2(l) = NO(g) + BrO31-(s)

Divide the reaction into two half-reactions

NO31-(aq) = NO(g)

Br2(l) = BrO31-(s)

Find these species on the Standard Reduction Potential Table

NO31-(aq) + 4H1+(aq) + 3e1- = NO(g) + 2H2O(l)

1/2Br2(l) + 3H2O(l) = BrO31-(s) + 6H1+(aq) + 5e1-

Both equations must involve the same number of electrons

5 X (NO31-(aq) + 4H1+(aq) + 3e1- = NO(g) + 2H2O(l))

3 X (1/2Br2(l) + 3H2O(l) = BrO31-(s) + 6H1+(aq) + 5e1-)

5NO31-(aq) + 20H1+(aq) + 15e1- = 5NO(g) + 10H2O(l)

1.5Br2(l) + 9H2O(l) = 3BrO31-(s) + 18H1+(aq) + 15e1-

Add the equations together to get a resultant.

5NO31-(aq) + 2H1+(aq) + 1.5Br2(l) = 3BrO31-(s) + 5NO(g) + H2O(l)

If you have 1.00 X 10^-4 (20.0) /40.0.

I got 5.00 X 10^-5 but I still feel like it should be ^-4?

1/ [4.6 X 10^-3)^2 X (1.5 X10^-5)^3

I got 1.4 X 10^19 but I feel like it should be to the power of 20?

6.5 X 10^-1/(1.0 X 10^-6)^2 (2.2 X 10^-4)

I got 3.0 X 10^15

Correct?

So I know the equation is

[C]^c[D]^d/[A]^a[B]^b

Where A and B are the reactants and C and D are the reactants. and the powers are the coefficients of the products/reactants.

My question is, if you only had a solid product, wouldn't that give you an answer of 0 because you have no liquid or aqueous products?

So for this lab I am supposed to find the slope of the graph...

Make a graph of the concentration versus the reaction rate. Draw a best-fit line and calculate the slope of the line.

Based on this data

Concentration

Reaction Rate

0.01 mol/L 1/ 5.4 sec = 0.18518518518 sec = 0.19 sec

0.009 mol/L 1/ 5.9 sec = 0.16949152542 sec = 0.17 sec

0.008 mol/L 1/ 6.8 sec = 0.14705882352 sec = 0.15 sec

0.007 mol/L 1/8.3 sec = 0.12048192771 sec = 0.12 sec

0.006 mol/L 1/10.6 sec = 0.09433962264 sec = 0.0943 sec

0.005 mol/L 1/14.0 sec = 0.07142857142 sec = 0.0714 sec

I was told to use reaction rate = 1/ reaction time (inverse) and I got a slope of 0.048444 mol/L/ sec which I rounded off to 0,05 mol/L / sec

Consider the following two reactions:

5 Fe2+(aq) + MnO41-(aq) + 8 H1+(aq) = 5 Fe3+(aq) + Mn2+(aq) + 4 H2 O(l)

2 MnO41-(aq) + 5 C2O42-(aq) + 16 H1+(aq) = 2 Mn2+(aq) + CO2 (g) + 8 H2 O(l)

Both of these reactions result in the purple permanganate (MnO41-(aq)) ion reacting to form the colourless manganese (II) ion. The difference is that the first reaction happens in a few seconds, while the second occurs over several minutes. Explain why this so, based on what you know of chemical reactions and what you can see in these two reaction equations.

The first reaction would have more concentration ( solvent would be able to dissolve in solute) and as stated above the chance of a collision happening increases so the number of collisions that result in a chemical reaction increases as well. As the number of effective collisions increases, the rate of reaction increases.

I am currently doing a lab on reaction time, concentration etc. Couple things I'm confused about, though. In my notes it says reaction rate = change in concentration over time, but for this lab, my teacher has told us to simply take the inverse of the reaction time (use our calculator) and then to make a graph of concentration vs reaction rate and take the slope of the line from the graph. For that part could I not just use the formula for slope from the data I have

i.e if the first reaction rate is 2 and the next is 3 and the concentration is 45 and 3 (just throwing out random numbers) you could have 3-2/45-3 and then add all answers together?

Thanks!

In the Bohr model of the hydrogen atom, the electron revolves around the nucleus and has a mass of 9.1 x 10^-31 kg.  If the radius of the orbit of the electron is 5.3 x 10^-11 m and the electron makes 6.6 x 10 ^15 r/s, find

A)

The acceleration of the electron

So I understand the formula is Ac= 4pi^2 X R/T^2

I also know R= 5.3 X 10^-11

T= 1/F or 1/6.6 X10^15

So it SHOULD be

Ac= 4pi^2 X 5.3 X10^-11/ (1/6.6X10^15)^2

But I'm getting the right answer (9.1 X10^22). I think there is something wrong with my operations, but, I'm not sure

A 2.00 kg stone is whirled in a circle by a rope 4.00 m long, completing 5 revolutions in 2.00 s.  Calculate the tension in the rope if the stone is rotated horizontally on a smooth frictionless surface.

I don't want someone to just do it for me, I want to make sure I'm understanding correctly.

The above question would mean that T= 2.5 (5/2) M= 2.00 kg and R= 2 (Radius= half the diameter)? Because I'm not getting the right answer.

If you have 170.5 why would the answer be 1.71 * 10^2

Shouldn't it be 1.7 * 10^2?

A bomber, diving at an angle of 53o with the vertical, releases a bomb at an altitude of 730 m. The bomb hits the ground 5.0 s after being released.

(a) What was the velocity of the bomber?

So what I did was I used the formula y=Vi * T +1/2A *T^2

-730= vi (5.0) +1/2 (-9.8) * 5^2

The answer ended up being -121.5 m/s (after someone on here showed me where I went wrong)

The answer is 2.2 * 10^2 but I fail to see why you divide by cos 53 and not multiply by sin 53 instead? I was taught that when dealing with x you deal with cos and y is sin?

A bomber, diving at an angle of 53o with the vertical, releases a bomb at an altitude of 730 m.  The bomb hits the ground 5.0 s after being released.

(a)    What was the velocity of the bomber?

So what I did was I used the formula y=Vi * T +1/2AT *T^2

-730= vi (5.0) +1/2 (-9.8)(5.0) * 5^2

The answer ended up being -12.5 m/s and then I did sin of 53 degree time -121.5.

The answer is 2.2 * 10^2

Can someone help?

That doesn't have iTunes just to charge, does that make my data available for people to see when they use that computer?

I am pretty close with my manager and supervisor and maybe a few others at work. My manager left for a while (he quit and then came back two months later) and while he was gone we went out for coffee a couple of times and my supervisor has already said she'll come (I guess I would call her a friend). Is it ok to invite them?

Like if I just plug it into a computer that doesn't have iTunes on it just to charge it, can they see my data/browsing history and what not?

I just have a question about the formula. Lets say you have a velocity vs time graph and it wants to know how far of a distance you have travelled after a certain number of seconds when the velocity is not constant.

The formula is d= 1/2(vf+vi)+(t)

Where d is distance

vf= final velocity

vi= initial velocity

t= time (number of seconds.)

Right?

I know you draw a tangent to what you're trying to find but I don't really get it. If I wanted to use a derivative could I being that I only have sets of points? If so, how? Help please!

( 1.4 x 10^2 )( 3 x 10^7 )

The answer is 4.0 X 10 ^3. I thought you multiplied 1.4 X 3= 4.2 and then added the exponents so shouldn't it be 4.2 X 10^9?