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Physics force question?
A 36.5 kg person stands on a 73 kg platform.
He pulls on the rope that is attached to the
platform via the frictionless lower-right pul-
ley. He pulls the rope at an angle of 32◦ to the
horizontal, as shown in the figure below.
Assume: g = 9.8 m/s2 . Ignore friction.
The platform remains level.
If he pulls the platform up at a steady rate,
how much force is he pulling on the rope?
1. F = 715.4 N
2. F = 536.55 N
3. Cannot be determined.
4. F = 643.86 N
5. F = 804.825 N
6. F = 429.24 N
7. F = 357.7 N
8. F = 1073.1 N
9. F = 268.275 N
Also:
In Part 1 we assumed that the platform re-
mains level. This is a bad assumption.
However, if the man were pulling straight
up on the rope, the forces will be balanced
and the platform should remain level.
1. Bad assumption
2. Good assumption
3. Cannot be determined
1 AnswerPhysics1 decade agoPhysics problem regarding pulleys and inclined planes?
A 6.4 kg mass on a frictionless inclined surface is connected to a 2.5 kg mass. The pulley is massless and frictionless, and the connecting string is massless and does not stretch.
The 2.5 kg mass is acted upon by an upward force of 4.9 N, and thus has a downward acceleration of only 4.9 m/s2.
The acceleration of gravity is 9.8 m/s2 .
What is the tension in the connecting
string? Answer in units of N.
Also, what is the angle theta?
1 AnswerPhysics1 decade agoHelp with physics/tension problem?
Two weights are suspended as shown in the
diagram. On the left, a weight of 46 N is
suspended from its upper-left by a string of
tension T1 angled at 40◦ with the horizontal.
A string carrying tension T2 is stretched be-
tween them angled at 11◦ with the horizontal.
On the right, the unknown weight W2 is also
suspended from its upper-right by a string of
tension T3 angled at 47◦ with the horizontal.
The acceleration of gravity is 9.8 m/s2 .
1 AnswerPhysics1 decade agoProjectile motion question?
A golf ball leaves the ground at an angle θ
and hits a tree while moving horizontally at
height h above the ground.
If the tree is a horizontal distance of b from
the point of projection, what is tan θ?
1. tan θ = 3h/b
2. tan θ =5b/h
3. tan θ =6b/h
4. tan θ =2h/b
5. tan θ =h/b
6. tan θ =4h/b
2 AnswersPhysics1 decade agoDoes anyone else love Mello (Death Note)?
Despite being male, I am strangely attracted to him.
12 AnswersComics & Animation1 decade agoMovie Question?
Is there a movie that the phrase "You can run but you can't hide " came from?
6 AnswersMovies2 decades ago
