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Silence Glaive
Ordering Mind-Body Solutions?
I'm ordering several mind-body solutions from "most physical" to "least physical". I have ordered them as follows, but I was wondering if someone could make suggestions if need be (a.k.a I put them in the wrong order). Thanks in advance!
Physicalism
- Behaviouralism
- Functionalism
- Identity Theories
- Minimal Physicalism
- Epiphenomenalism
Dualism
- Property Dualism
- Cartesian Dualism
Idealism
1 AnswerPhilosophy9 years agoBinomial/Normal Distribution Question?
A store manager believes 42% of her customers are repeat business (have visited her store within the last two weeks). Assuming that she is correct, what is the probability that out of the next 500 customers, between 200 and 250 customers are repeat business?
I have approximated this question using normal distribution, but my issue starts at the z-scores. I solved the z-score of 200.5 to be -.86 and the z-score of 249.5 to be 3.58. I cannot get a percentile from 3.58 to subtract the percentile of -.86. In fact, I don't think a percentile for that score exists.
I don't think I solved previous parts of this question wrong, but I'm not sure. This is what I did.
mu = 500 * .42
= 210
sigma = square root (210 * (1-.42))
= 11.036
200< X < 250 = 200.5 < X < 249.5
Z = (200.5-210)/11.036
= -0.861
Z = (249.5-210)/11.036
= 3.580
The approximate answer is supposed to be 82% to 83%.
1 AnswerMathematics10 years agoCombinations Question?
From a deck of 52 cards, how many different four-card hands could be dealt which include one card from each suit?
The answer is 12696, but I'm not sure what steps to take to get this answer. I thought it would be 52C4*(4C1)^4, but I'm wrong.
1 AnswerMathematics10 years agoWhat does this Japanese sentence mean?
だれかとデートをしたい時、何と言ってその人を誘いますか。
I'm pretty sure the first part means "When you want to go on a date with someone..." but I can't figure out the second part.
Help? :)
Thank you in advance.
3 AnswersLanguages1 decade agoSequence (Math) Question?
How would you figure out the general terms (arithmetic and geometric) if you are given the first term of a sequence and two other random numbers from it?
1 AnswerMathematics1 decade agoTrig Identities Question?
I have to prove this as true:
cos^2x - sin^2x / cos^2+ sinxcosx = 1-tanx
I've been agonizing over this for about an hour. The farthest I ever got to was -sinx=1-cosx, but that's obviously wrong. This is what I have now:
cos^2x - sin^2x / cos^2+ sinxcosx = 1-(sinx/cosx)
cos^2x - (1-cosx)^2x / cos^2+ sinxcosx = cos^2x-(1-cos^2x/cos^2x)
cos^2x - (1-cosx)^2x / cos^2+ sinxcosx = cos^2x+sinxcosx-(1-cos^2x+sinxcosx/cos^2x+sinxcosx)
cos^2x - (1-cosx)^2x = cos^2x+sinxcosx-(1-cos^2x+sinxcosx)
cos^2x-cos^3x = (cos^2x-cos^4x+sinxcos^3x+sinxcosx-sinxcos^3x+sin^2xcos^2x)
-cos^3x = -cos^4x+sinxcos^3x+sinxcosx-sinxcos^3x+sin^2xcos^2x
But I think this is utterly wrong, and even if it isn't, I don't know where to go from here...
1 AnswerMathematics1 decade agoIs There a Japanese Equivalent of "Abracadabra"?
Are there any sort of common "incantations" in Japanese that function like the English "abracadabra"?
2 AnswersLanguages1 decade agoExponential Depreciation Question?
You want to buy a new car, and you have investigated the trade-in value of your current car. Three months ago, the trade-in value was $3200. The trade-in value is now $3125. What will be the trade-in value of your car six months from now if it is depreciating exponentially?
I tried doing this question and got as far as:
3125=3200(1/2)^3/d
3125=1600^3/d
But I'm not sure if it's right, and I don't know what to do anymore...
1 AnswerMathematics1 decade agoSolving Exponential Equations?
There are several questions like the following that were assigned for homework, yet my teacher did not explain how to do them at all. I've tried, but I keep on getting the wrong answer.
9^2x+1 = 81(27^x)
I multiplied 81 by 27 to be 2187^x, and then I made the bases equal to three. However, my final answer after everything ended up being 2/3 when it should be 2. Could someone explain how to do this?
4 AnswersMathematics1 decade agoJapanese: When using -to omotta at the end of a sentence, is everything before that in present or past tense?
I wrote this sentence for an assignment:
でも、私はあいつのバンドが恐ろしくて、顔がおかしいと思った.
Demo, watashi wa aitsu no bando ga osoroshikute, kao ga okashii to omotta.
(I am supposed to write this in informal language, by the way. I know you would never normally say something like this XD)
I want to say "But I thought his band was terrible and his face was weird."
Do I conjugate the adjectives in past tense, or does the usage of -to omotta make the entire sentence in past tense already?
Thank you~
6 AnswersLanguages1 decade agoQuadratic-Linear Systems Problems?
1. A quadratic function, f, and a line, g share the same y-intercept of -3. If f(2)=1, f(4)=-11, and g(4)=9, determine the equations defined by f(x)=ax^2 + bx + c and g(x)=mx+b.
I figured out that for the linear system, the answer is 3x-3. However, I'm not sure how to do the quadratic one since there's a and b...how would you isolate, or what else can you do?
2. Determine the equations of the lines that have a slope of -6 and intersect the function once, twice, or never.
f(x) = 3x^2 + 6x -7
For this question, I have no clue what to do besides that the equation above should be equal to -6+b. However, I end up getting 0 = 3x^2 + 12x - 7 - b, and I don't know what to do from there. Without the -b, I would use the quadratic formula...but what do I do with the -b?
1 AnswerHomework Help1 decade agoQuadratic-Linear Systems?
1. A quadratic function, f, and a line, g share the same y-intercept of -3. If f(2)=1, f(4)=-11, and g(4)=9, determine the equations defined by f(x)=ax^2 + bx + c and g(x)=mx+b.
I figured out that for the linear system, the answer is 3x-3. However, I'm not sure how to do the quadratic one since there's a and b...how would you isolate, or what else can you do?
2. Determine the equations of the lines that have a slope of -6 and intersect the function once, twice, or never.
f(x) = 3x^2 + 6x -7
For this question, I have no clue what to do besides that the equation above should be equal to -6+b. However, I end up getting 0 = 3x^2 + 12x - 7 - b, and I don't know what to do from there. Without the -b, I would use the quadratic formula...but what do I do with the -b?
1 AnswerMathematics1 decade agoRevenue Word Problem in Quadratics?
I have a math assignment due on Monday that I was trying to do, and all was going well until I hit the last question. My teacher did not go over this problem with the entire class, so I unfortunately missed the lesson, and I'm not 100% sure what to do, especially since we haven't really worked with functions yet. This is the question:
The demand function for a new product is p(x)=-5x+22, where x is the number of items sold in thousands and p is the price in dollars. The cost function is C(x)=3x+15.
A) State the corresponding revenue function.
I'm pretty sure that is R(x) = x p(x)
B) Find the corresponding profit function.
I think it's P(x) = R(x) - C(x)
***C) Find the value of x that will maximize profit.
This is where things go wrong. I think I should sub in the demand function into R(x) = x p(x), but do I only sub it into the p(x) part and leave the x in front of the p kinda just there? I'm sorry, math isn't my forte, so I'm not too sure about this.
D) Find the break even quantities.
Once I get the value of x, shouldn't I just find the zeroes of the equation or use the quadratic formula?
E) Sketch the graph of the profit function.
I suppose I'll get an equation at this point, and graphing isn't a problem for me. It's just C) where I'm not sure where to go...
1 AnswerMathematics1 decade agoSimplifying this expression?
I'm a little confused as to which comes first: the distributive law or the expansion. It'll be easier to understand if you see the question:
(x-1)^2(x+3)^2-(x+1)^2(x-2)^2
I've tried this several times, but I can't get the answer. Could any of you show me how? I'm not sure if I should distribute the - to the (x+1)^2 first, or if I should expand and simplify that first, or what.
3 AnswersMathematics1 decade agoHalf-Chinese, Half-Canadian female in Japan...?
I'm often thought to be either full Japanese or full white by non-Asians, and I'm thought to be either full Korean, full Japanese, or half-Asian by Asians. I'm mostly mistaken for being fully Japanese or fully Korean though in general. I do have small double eyelids, but I noticed that some Japanese have double eyelids (whether it be natural or due to the usage of that double eyelid glue, I'm not sure). However, sometimes it looks like I don't have double eyelids depending on the angle and the makeup I'm wearing. My eyes are almond shaped, I suppose. In other words, not fully Asian nor fully white, but closer to the Asian side.
I'm semi fluent in Japanese (I probably have an accent, but I can watch raw versions of dramas and anime and understand. I understand better than I can speak though due to not having anyone to speak to in Japanese), and I know many basic kanji (I can recognize them more than I can write them, but I can write basic kanji as well as all hiragana and katakana syllables).
I am going to be going on vacation in Japan for 2 weeks, and I'm curious about two things:
- How do I say "Half-Chinese, half-Canadian" in Japanese?
- How will the Japanese people GENERALLY perceive me?
4 AnswersJapan1 decade agoAnalytic Geometry Proof?
The first part of a question I had to answer was:
Given a quadrilateral with vertices at S(-3, 4), T(1, 2), U(3, -4), and V(-5,-2), prove that the midsegments of this quadrilateral form a parallelogram.
After proving that by showing that the opposite sides were parallel, I was asked:
Is this property true for all quadrilaterals? Justify your answer.
How would I justify that?
1 AnswerMathematics1 decade agoQuadratic Word Problem?
The side of one square is 3 cm longer than the side of another square. If the sum of the areas of the two squares is 65cm^2, find the lengths of the sides of each square.
4 AnswersMathematics1 decade agoTrigonometry Word Problem?
The police are trying to catch the operator of a pirate radio station. They park two vehicles with directional antennas on the side of a straight section of road 2000m apart. They aim the antennas to find the pirate station signal, which is coming from a location somewhere between them. From Constable Abel's vehicle, the angle is 70 degrees. From Constable Barker's vehicle, 30 degrees. Which police officer is closer to the pirate radio station, and how far away, to the nearest meter, is it from that officer?
1 AnswerMathematics1 decade agoTrigonometry Word Problem?
The police are trying to catch the operator of a pirate radio station. They park two vehicles with directional antennas on the side of a straight section of road 2000m apart. They aim the antennas to find the pirate station signal, which is coming from a location somewhere between them. From Constable Abel's vehicle, the angle is 70 degrees. From Constable Barker's vehicle, 30 degrees. Which police officer is closer to the pirate radio station, and how far away, to the nearest meter, is it from that officer?
The answer should be C.A. and 102m away, but I keep on getting C.B. by 1015m. I'm clearly doing something wrong, but I have no clue as to what.
1 AnswerMathematics1 decade agoTrigonometry Word Problem?
Fiona is repairing the wiring on a radio broadcast tower. She is in the basket of the repair truck 40m from the tower. If she looks up at an angle of 42˚ she can see the top of the tower. She can see the base if the tower if she looks down at an angle of 32˚. How high is the tower to the nearest tenth of a meter?
----
I tried this question out, and I got 50m. The answer should be 61m. I thought I was supposed to solve tan42˚=x/40, and then I tried using the sine law (c/sine42˚=40/sine32˚), and I haven't gotten the right answer at all.
2 AnswersMathematics1 decade ago