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Could someone please solve this Chemistry question for me?
Based on the following chemical equation, answer the questions below.
NaH+B2H6--------NaBH4
a. Balance the above equation
b. How many grams of NaBH4 (sodium borohydride) will be prepared theoretically by reaction between 12.5g of NaH (sodium hydride) and 7.50g of B2H6 (diborane)?
c. Which reactant is limiting?
d. If the actual yield of NaBH4 was 12.0g, what was the percent yield of NaBH4?
Thanks in advance for your answers.
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