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  • Help with PH calculation - baby steps please?

    50ml of water

    50ml of 1M acetic acid with a Ka of 1.75X10-5

    (so that = 0.5 molar solution in total right?)

    and 1ml casein

    Ka = [H]X[A]/[HA] = 1.75 X 10-5

    pH= PKa+ log[A]/[HA]

    PKa= -log(Ka) = 4.75

    What is [H] [A] and the resulting ph?

    PLEASE talk me through in baby steps explaining how to get the pH

    Chemistry6 years ago

  • How to calculate PH from Ka?

    A solution contains:

    50ml of water

    50ml of 1M acetic acid with a Ka of 1.75X10-5

    and 1ml casein

    How do I calculate the PH? Step by step please

    2 AnswersChemistry6 years ago