Carlos

what do you call atoms that have more than one ionic form(ex. Ti+1, Ti+2, Ti +3, Ti+4)?

Docters think ADHD is caused by ssesame street.

Just look at this in its entirety. (pay close attention to the victim on the right).

ONly reply after you have watched the whole thing

http://www.youtube.com/watch?v=SA_WDHo-kaw&feature...

Docters think ADHD is caused by ssesame street.

Just look at this in its entirety. (pay close attention to the victim on the right).

ONly reply after you have watched the whole thing

Is it better for me to have all A's(4.0GPA or damn close to it?)

I am planning on going into medical school after I get my Doctorate's in civil-engineering. Engineering is a given.So, what about medical school? Do I need to have a 4.0(obviously not a exact, more like approx.) in ALL my classes or just the ones for my pre-requisites?

Details: medical school like "I am going to get my 4-year degree to become a surgeon". Once I am in, I am IN, I am just talking about GETTINg accepted. I already took my MCAT back in my bachelor days(6-years ago). It is a pretty perfect score. The question only pertains to prerequisites(pre-med)

http://www.youtube.com/watch?v=c710UG7HXY0

http://www.youtube.com/watch?v=c710UG7HXY0

http://www.youtube.com/watch?v=bdY7Adc1LRM

would you do?

vena conteste a mi

vena conteste mi

vene, deca mi

where do I click? I don't see it

If g(x)=2x^2-7x-8, find g^-1(7)

If f(x)=(-x^2-16)/10, what is the range and domain of the function?

(Hint: I know the answer: if correct= 10 points

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

HOW did you get "x+1"

Show me how you got it like i showed you how to start it(step-by-step until you get to the step I am sking for)

I have asked this question 5 times and have gtotten bullshit results from it.You know why? Because these do not show their steps. PLEASE SHOW ALL YOUR STEPS

Thank you

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

HOW did you get "x+1"

Show me how you got it like i showed you how to start it(step-by-step until you get to the step I am sking for)

I have asked this question 5 times and have gtotten bullshit results from it.You know why? Because these do not show their steps. PLEASE SHOW ALL YOUR STEPS

Thank you

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

HOW did you get "x+1"

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

hhhhhuuuuuuhhh

HOW did you get "x+1"

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

HOW did you get "x+1"

hjfgtvfhdfh

Entry calculus observation: How does the numerator turn into "x-1"?

(Multiplying by conjugates won't work for this challenging problem. Instead, recall that

A^3-B^3=(A-B)(A^2+AB+B^2)

and

A^4-B^4=(A-B)(A+B)(A^2+B^2)

note that x-1=(x^(1/3))^3 -1^3 and x-1=(x^(1/4)) ^4 -1^4

=lim (x^(1/3) -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

x---1 --------------- ----------------------------------------

##### (x^1/4 -1) { (x^(1/3))^2 +(x^1/3)1 +1^2}

and , and note that and . This should help explain the next few mysterious steps.)

PLease explain how the numerator turns into "x-1"

This is the only step that I am asking to be explained.

Thank you (ignore the "#". I had to use this to space out the denominator because of yahoo's system of re-tabbing)

20 minutes ago - 4 days left to answer.

Additional Details

I simplified the numerator and solved(obtained) "x^(1/3) -1"

17 minutes ago

Kb: Using your method of simplifying, I simplify to

(x^1/3 -1)(x^3 +1)

x =x^1/3 -x^3 -1

HOW did you get "x+1"