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Omar
Math/Physics 11 help needed plz!?
I'm looking for the time of flight for a soccer ball kicked at a 40 degree angle and solved for the vertical velocity already.
Given:
Dy= 0ms
Viy= 6.04 m/s
acceleration of y = -9.8 m/s^2
Required: time = seconds
Let time = x
So, I'm using one of the 5 motions equations to solve for time:dy=(Viy)(x) + 1/2 (Acceleration of y) (x^2)0 m = (6.04 m/s) (x)-4.9 m/s^2)(x^2
and I'm stuck from here because I don't know how to solve for x if one is x^2.
I'm attaching a photo of how my teacher answered it in zoom, but it looks like she did it wrong. In her explanation she was explaining how she factored 4.9x, so the next line that I should have is:
-4.9x(x-1.23)=0, but 4.9x isn't a common factor, only x is, so my assumption is that the next line should be:
x(-4.9x+6.04)=0
but I don't know what to do after that.
The thing is, her answer was correct, it was 1.23 seconds, but it looks like the way she got to that answer isn't a proper method.
Hoping someone can help!
Thanks in Advance!
1 AnswerMathematics5 months ago
Find the domain and range of this equation: It is a square root equation.?
I added a picture because I couldn't get the square root sign to work.
I'm having difficulty isolating y.
I forget how to isolate when there are multiple operations. Do I do it in the order of PEMDAS?
I don't know where to pick at first and needed some help.
Thanks in Advance!
2 AnswersMathematics7 months ago
What is the inverse of this equation?
I have a snippit of the equation since i don't know how to make square root signs :(
Thanks in Advance!
3 AnswersMathematics8 months agoSimplify and State Restrictions: 2/(x^2+7x+12) + 5/(x^2+5x+6)?
My answer is as follows:
2/(x+3)(x+4) + 5/(x+2)(x+3)
= (2(x+3)(x+2))/((x+2)(x+3)(x+4)) + (5(x+3)(x+4))/((x+2)(x+3)(x+4))
= (2(x^2+2x+3x+6))/((x+2)(x+3)(x+4))+(5(x^2+4x+3x+12))/(x+2)(x+3)(x+4)
= (2x^2+10x+12)/((x+2)(x+3)(x+4)) + ((5x^2+35x+60)/(x+2)(x+3)(x+4))
Final Answer being:
(7x^2+45x+72) / ((x+2)(x+3)(x+4))
Restrictions are: x cannot be -2, -3, -4
Am I Right?
Thanks in Advance!
Mathematics8 months agoWhen simplifying and stating restrictions, when do you state restrictions on the denominators so that the equation doesn't equal zero?
From my understanding, you state restrictions after you have the equation in factored form.
Is this right?
Thanks in Advance!
Mathematics8 months agoSimplify and State Restrictions: (x^2-4x-5)/(x^2-3x-10) * (9x+3x^2)/(x^2-9)?
I answered it already, but I need help clarifying something or a few things.
So, the first step is to reduce and factor:
((x+1)(x-5))/((x-5)(x+2)) x (3x(x+3))/((x-3)(x+3))
= (x+1)/(x+2) * ((3x)/(x-3))
Final Answer is:
3x(x+1)/ (x+2)(x-3)
I have a question though about the 3x on the right side of the equation that is left over on the numerator, after the reduction, the equation looks like:
(x+1)/(x+2) * (3x)/(x-3)
I took the 3x and placed it in front of the (x+1) so its 3x(x+1) on the numerator. Is this the correct step to take when there is a co efficient that is left over on the right side?
Thanks in Advance!
Mathematics8 months agoFor F(x)=8x-5 determine f^-1(1)?
This is my answer, please tell me if I'm right or not.
f(x)=8x-5
y=8x-5
x=8y-5
(x+5)/8=(8y)/y
(x+5)/8=y
1+5/8=y
6/8=y
3/4=y
Therefore y=3/4.
3 AnswersMathematics8 months agoHow do I find the domain and range of: 𝑦 = 2[−3(𝑥 + 1)]^2 + 4 without graphing. And is it a function?
From my understanding, the absolute equation is in the form of:
y=a|x-h|+k, but i have a question; what transformation does the +2 at the beginning of the equation give?
2 AnswersMathematics8 months agoHow do i expand this factored equation? y=8(x+6)(x-9)?
I forget what to do with the 8 outside two sets of brackets. I remember without a number outside or variable you use the foil method, but I'm not sure what to do with an 8 outside the brackets.
Thanks in Advance!
3 AnswersMathematics8 months agoquestion about plotting the answer to this absolute equation: y=-3|2(-2-1)|+4 on a graph, answer is y=-14.?
Are the co-ordinates (-2,-14)?
2 AnswersMathematics8 months agoSimplify and State Restrictions: (2/x^2+7x+12)+(5/x^2+5x+6)?
I was able to factor the denominators, so it looks like:
2/(x+4)(x+3) + 5/(x+1)(x+6)
From there, I know I have to determine the lowest common denominator, but with factored form denominators of a simple trinomial, I'm not sure how to go about with it.
1 AnswerMathematics8 months agoSimplify and State Restrictions (x-4/x^2+8x+15) * (2x^2+7x+3/ x^2-16)?
my answer so far is this:
x-4 / (x+3) (x+5) * (2x+1) + 3 (2x+1) / ((x-4)(x+4))
1/ (x+3)(x+5) * ((2x+1)+3(2x+1)/(x-4)(x+4))
I am not able to complete the answer.
So, I managed to get up to:
((2x+1)+3(2x+1))/((x+3)(x+5)(x+4)
Thanks in advance for the help.
Mathematics8 months agoSimplify and State Restrictions (x^2-4x-5)/(x^2-3x-10) x (9x+3x^2/x^2-9)?
My answer is
3x^2+3x/x^2-1x-6
Am I Right?
5 AnswersMathematics8 months agoSimplify and State Restrictions (7x^2 +14x)/ 5x+10?
My answer was 7x/5.
Was I right?
Thanks in ADvance
1 AnswerMathematics8 months agoSimplify and State Restrictions (7x^2 +14x)/ 5x+10?
My answer was 7x/5.
Am I right?
Thanks in Advance
5 AnswersMathematics8 months agoSimplify and State Restrictions: (5x^3y^2/27x) x (9xy/25x^2y^2)?
I only got to the point of making it all under one line so it looks like
(5x^3y^2)(9xy)/(27x)(25x^2y^2)
Am I supposed to group like terms for the top and bottom so it's (45x^4y^3)/(675x^3y^2) ?
and from there simplify so the answer is
9xy/75?
Restrictions being x cannot equal 0 and y cannot equal 0?
Thanks in Advance!
2 AnswersMathematics8 months ago