yuko225

given: a(t) = -32 feet per sexond per second.

problem: with what initial velocity must an object be thrown upward (from ground level) to reach the top of the Washington Monument (roughly 550 feet)?

1) took integral of [a(t)] = -32t + C; so velocity function is [v(t) = -32t + C]

2) because it's from stopped, t = 0; v(0) = -32(0) + C => C = V

3) took integral of v(t) = -16t^2 + V + C; so position function is [s(t) = -16t^2 + V(t) + C]

4) because it's from ground level, t = 0; s(0) = -16(0)^2 + V(0) + C => C = S

5) found where s'(t) = 0; -32t + V = 0; t = (V/32)

6) evaluated [s(V/32) = 550] => -16(V/32)^2 + V(V/32) + S = 550

this is where i'm stuck.

i need to solve for V, but what do i do with the constant S?

do i set it equal to 0 because everything is from t=0?

please help anyone?

given:

a(t) = -9.8 feet per second per second due to gravity. neglect air resistance.

problem:

with what initial velocity must an object be thrown upward (from a height of 2 meters) to reach a maximum height of 200 meters?

so i took the integral of a(t)

S[-9.8]dt = -9.8t + c;

so that means velocity function is (-9.8t + c).

what do i do from here?

how do i find the position function?

do i take V(0) = [-9.8t + C = 200]?

do i take the integral of the velocity function instead?

S[(1/2)(-9.8t^2) + C(1)t + C(2)]dt?

what do i do here?

no matter what i tried i can't get the answer: 62.3 m/sec

i was in the military and sometimes i just want to say i was never in the service to stay off the radar.

is it illegal, as a veteran, to say you were never in the service? that you never went to "x" country, etc...

because i know it's illegal as a civilian to say you were in the service.

just wondering if it works the other way around.

isn't this the same as looking inside someone's home? is that legal? or considered a bad thing? i'm wondering.

i was working inside my garage and every single car that drove by, the driver was already looking at me as he/she drove past.

a few of them look away instantly like "oh i hope he didn't catch me looking".

i have the door open so i can grab tools out my truck in the driveway. if the garage door was closed i bet no one would look cause it's just like every other house on the block. but just cause the door is open, why do people always have to look inside and see my ****??

seriously.. is it just me?

i actually make an effort not to look in people's garages cause it's their ****.

like mind your own dam business.

when you jump out the plane and pull the parachute, do you fall at a steady rate?

or do you gradually fall faster and faster (with parachute applied of course)

would it make sense to release the parachute and pull another? if that makes sense?

wouldnt it be better to put out the fire if airplanes drop ice cubes?

it will absorb a lot of the heat and then turn into water to flush out the small spaces.

f(x) = x^3

f^-1(x) = cube root(x)

f(x)' = 3x^2

how is the derivative of (f^-1) = 1/(3 cuberoot(x))?

isn't it supposed to be 1/3 x^(-2/3)? or -2/3 cuberoot(x)?

f(x) = x^3 +2x -1, a =2

f'(x) = 3x^2 + 2 > 0 (i don't know what the point of this is, can someone explain?)

f(1) = 2 => f^-1 (2) = 1

(f^-1)'2 = 1/ (f'(f^-1(2))) = 1/f'(1) = 1/5

ok where did the f(1) come from?

why is it f(1)?

seems like the book pulled an arbitrary number out its ***.

why not use f(15)?

what is a=2 supposed to mean?

whatever happened to yahoo chess?

you go into rooms, make games, and play with other users..

i can't find it in the library of games cause yahoo is fukcing retarded and changed everything.

so i'm really confused with this section..

i thought quotients were hard, but this section really makes no sense to me.

can someone tell me the difference between the two?

dy/dx

d/dx

can you use it in this example?

x^3 - xy + y^2 = 7

how does it go from d/dx => dy/dx?

d/dx x^3 agrees with d/d(x) so it's 3x^2

d/dx y^3 disagrees so it's 3y^2

how does that even make sense?

it's the same derivative whether or not it agrees or disagrees.

this book is so ******* terrible, it jumps all over the place and doesn't explain clearly.

then the professor's lecture uses different symbols and notations and confuses me even more.

wtf is f'(u) and f(u)'

so far this is all i learned from this chapter:

xy= 1, we need to seperate y.

y = 1/x

that's all i absorbed.

where does dy/dx come from?

why does it say d/dx?

why are they different if the derivatives are the same?

why does the book keep confusing readers?

don't leave out any steps please.

ELI5 (explain like i'm 5)

this is the books example, and i can't do any homework because i can't make sense of the example.

simplify the derivative of a quotient.

bear with me, it may get slightly confusing with brackets.

so it might be easier if you write it out, i know it's a lot of work, but please help, i'm so lost and confused.

x/(x^2+4)^(1/3)

or in other words

x/(cube root(x^2+4))

step 1) i got [(x^2+4)^(1/3)](1) - (x)[(1/3)(x^2+4)^(-2/3)(2x)]

step 2) how does the book get (1/3)(x^2+4)^(-2/3)[(3(x^2+4)-(2x^2)(1))/(x^2+4)^(2/3)] as the next step????????????

then the final answer (x^2+12)/3(x^2+4)^(4/3)

where does that 3 come from [3(x^2+4).....]?

how did the book factor out (1/3)(x^2+4)^(-2/3) in the front?????

did i miss something in algebra?

this makes no sense to me whatsoever.

i even tried to switch it and use product rule instead, but that's even more confusing.

ln[(1+e^x)/(1-e^x)]

u = [(1+e^x)/1-e^x)]

= ln u'/u

....yea that's about as far as i can go.

the book only has 1 example using ln,

and it's

lnx = 1/x which is basically (x'/x)

what do i do here?

multiply conjugate? find derivative first?

what happens to the ln?

the end result will be a fraction over a fraction. so how do i input a natural log function with that?

ln u' - ln u?

seriously wtf happened to my printer??

i have an hp 4680 PIECE OF ****

been working FINE for the past 3 months.

and now i turn it on and i get ERROR printer offline.

like WTF HP....

why do printers ******* do this.

ink is filled, cartridge aligned, everything is fine.

but all of a sudden it's ******* offline when i turn it on and off and on and off and it won't read my printer.

wtf is wrong with hp products

so in order for a limit to exist

"f(x) cannot increase or decrease without bounds as x approaches c."

(word for word from the book)

so an example of this would be vertical asymptotes such as y=tan right?

in other words "infinity".

so in this case there is no limit.

well then can someone explain what an infinite limit is then?

aren't all limits technically an infinite limit?

x->c-

x->c+

as [x] approaches [c] from either side the limit becomes .0000000000000000000(infinity) [c], the closer x gets to [c] no?

so how can there be a restriction on limits as x-> c(+,-), if you can't have "f(x) cannot increase or decrease without bounds as x approaches c"??

i'm finding this whole limits chapter very contradicting to its own statements

how do i interpret this?

the book gives me a triangle with (1 - 4x^2) , 1, 2x

like wtf, how did they even get those?

where did they even get those?

did i miss something in trig?

if you become a victim of sleep paralysis would you be able to move out of sheer will power?

i had sleep paralysis a while back and i remember inwas able to move a leg because i knocked the remote control off my bed.

but other than that, my head was super dizzy feeling, couldn't move any other part of my body. and next thing i know, i woke up because i hears the toilet flush with a crack of sunlight.