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Lv 611,632 points

Mekkah

Favorite Answers28%
Answers2,302

Basically, I play pokemon, call of duty, league of legends, maplestory, and a lot more! Feel free to email me and I'd love to help you any way I can. (:

  • Does anyone want to pokemon battle on xy?

    Rules:

    All pokemon allowed including legendaries.

    No putting to sleep more than 1 pokemon at a time.

    No OHKO moves like sheer cold, fissure, etc.

    My FC is 4313-0626-5328

    You can also contact me at latiosou@yahoo.com

    Rules I guess can maybe be changed.

    2 AnswersVideo & Online Games7 years ago
  • At what displacement of a Simple Harmonic Oscillation is the energy half kinetic and half potential?

    Basically what the title says. This should be extremely easy but the answer it says in the book is wrong. =/

    2 AnswersHomework Help8 years ago
  • At what displacement of a Simple Harmonic Oscillation is the energy half kinetic and half potential?

    Basically what the title says. This should be extremely easy but the answer it says in the book is wrong. =/

    2 AnswersPhysics8 years ago
  • Who wants to pokemon battle? (Gen 4)?

    FC: 5415 1826 5050

    My email me latiosou@yahoo.com

    If you know what standard OU is then standard OU.

    If not, then know that these pokemon are BANNED and NOT allowed.

    Also sleep clause/evasion clause. Google those if you don't know what they are.

    Also no hacks or hacking.

    Arceus

    Darkrai

    Deoxys

    Deoxys-A

    Deoxys-D

    Deoxys-S

    Dialga

    Garchomp

    Giratina

    Giratina-O

    Groudon

    Ho-Oh

    Kyogre

    Latias

    Latios

    Lugia

    Manaphy

    Mew

    Mewtwo

    Palkia

    Rayquaza

    Salamence

    Shaymin-S

    Wobbufett

    Wynaut

    3 AnswersVideo & Online Games8 years ago
  • Find the area A inside r = 1 + cos θ and outside r = cos θ.?

    Find the area A inside r = 1 + cos θ and outside r = cos θ.?

    This is the last problem on my HW assignment please help me. :(

    I understand A=1/2 integral (f(theta))^2 d(theta) but I don't see how I am supposed to get the area they are looking for? Like the area inside of one but outside another. I tried doing these 2 individually and subtracting them but the answer I got was wrong. =/

    Any advice with this would be appreciated.

    1 AnswerMathematics8 years ago
  • Determine which property of the real numbers is used. (Select all that apply.)?

    Determine which property of the real numbers is used. (Select all that apply.)

    5 + (x − 52) = (5 + x) − 52

    A. Commutative property

    B. Associative property

    C. Identity property

    D. Inverse property

    E. Distributive property

    1 AnswerHomework Help8 years ago
  • Chemistry Help (thermochemistry)?

    Any help with these would be greatly appreciated.

    Consider the following thermochemical equations :

    8Mg(s) + Mg(NO3)2(s) → Mg3N2(s) + 6MgO(s) ΔH°rxn = –3884 kJ

    Mg3N2(s) → 3Mg(s) + N2(g) ΔH°rxn = +463 kJ

    2MgO(s) → 2Mg(s) + O2(g) ΔH°rxn = +1203 kJ

    Use the above equations to calculate the ΔH°f (in kJ/mol) of solid Mg(NO3)2.

    A. +188 kJ/mol

    B. –188 kJ/mol

    C. +94 kJ/mol

    D. –94 kJ/mol

    E. –222 kJ/mol

    Magnesium metal reacts with hydrochloric acid according to the following equation:

    Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

    To determine the enthalpy change for this reaction, 0.158 g of Mg metal is combined with enough HCl to make 100.0 mL of solution in a coffee-cup calorimeter of negligible heat capacity. The HCl is sufficiently concentrated so that the Mg completely reacts. The temperature of the solution rises from 25.6oC to 32.8oC as a result of the reaction. Find the ΔHorxn (in kJ/mol) for the reaction as written. Use 1.00 g/mL as the solution density and the specific heat capacity of the solution = 4.181 J/g oC.

    A. –3.0 x 103 kJ/mol

    B. –1.9 x 104 kJ/mol

    C. –4.6 x 105 kJ/mol

    D. –6.7 x 105 kJ/mol

    E. –4.6 x 102 kJ/mol

    A 7.45 g sample of solid LiOH is completely dissolved in 120.00 g of water at 23.25°C contained in a calorimeter with a heat capacity of 11.7 J/°C. The specific heat capacity of the solution produced was 4.20 J/g•°C, and final temperature reached was 34.91°C. How much heat was produced by the dissolution?

    A. 6.24 kJ

    B. 0.544 kJ

    C. 0.136 kJ

    D. 6.38 kJ

    E. 6.11 kJ

    1 AnswerHomework Help9 years ago
  • Help with online math hw integrals?

    Hey, I'm doing math hw I need a bit of help with these integrals. It's online though so can someone please do these and see what answer they get since idk what I'm doing wrong. If you could show work that we be even better and I would appreciate any help you guys could give me.

    Evaluate the /definite/ integral.

    Integral |1 8e^x(sinx) dx

    |0

    I get -6.68 for this one. Computer says its wrong. :(

    Integral |e 5x(lnx) dx

    |1

    Not sure how to do this one.

    Integral |(pie/6) 5(cos^3x)(√sinx) dx

    |0

    No idea where to start with this one.

    And finally, evaluate the /in/definite integral

    Integral ln(25+x^2) dx

    I got x(log(x^2+25)-2)+(10arctan(x/5)) but the computer says its wrong.

    Additional Details

    @Rick Flair

    Actually, I attend a major university, and I am not doing an "online" agree. All my classes have an "online" portion of the class, usually for homework or some other part.

    There are /30/ questions on this online homework. I need help with /4/ of them.

    /2/ of which I got an answer I'm pretty sure is right but I just need someone to help me check.

    And there are another 50 regular, on paper which I've already done.

    So I accept your apology.

    1 AnswerMathematics9 years ago
  • Help with online math hw integrals?

    Hey, I'm doing math hw I need a bit of help with these integrals. It's online though so can someone please do these and see what answer they get since idk what I'm doing wrong. If you could show work that we be even better and I would appreciate any help you guys could give me.

    Evaluate the /definite/ integral.

    Integral |1 8e^x(sinx) dx

    |0

    I get -6.68 for this one. Computer says its wrong. :(

    Integral |e 5x(lnx) dx

    |1

    Not sure how to do this one.

    Integral |(pie/6) 5(cos^3x)(√sinx) dx

    |0

    No idea where to start with this one.

    And finally, evaluate the /in/definite integral

    Integral ln(25+x^2) dx

    I got x(log(x^2+25)-2)+(10arctan(x/5)) but the computer says its wrong.

    1 AnswerMathematics9 years ago
  • Help with online math hw integrals?

    Hey, I'm doing math hw I need a bit of help with these integrals. It's online though so can someone please do these and see what answer they get since idk what I'm doing wrong. If you could show work that we be even better and I would appreciate any help you guys could give me.

    Evaluate the /definite/ integral.

    Integral |1 8e^x(sinx) dx

    |0

    I get -6.68 for this one. Computer says its wrong. :(

    Integral |e 5x(lnx) dx

    |1

    Not sure how to do this one.

    Integral |(pie/6) 5(cos^3x)(√sinx) dx

    |0

    No idea where to start with this one.

    And finally, evaluate the /in/definite integral

    Integral ln(25+x^2) dx

    I got x(log(x^2+25)-2)+(10arctan(x/5)) but the computer says its wrong.

    3 AnswersMathematics9 years ago
  • Help with online math hw integrals?

    Ok, I'm doing online homework and it says my answers are wrong even though I think I'm doing them right. Any help with these are appreciated and if you could show your work that would be even better.

    Integral of (x^5)/(x^2+1)^2

    I get (x^2/2) - 1/(2(x^2+1)) - log(x^2+1) but I don't know what I did wrong. =/

    1 AnswerMathematics9 years ago
  • How many moles of lead(II)silfide are in 5.42 ft^3? (density to moles question)?

    The mineral galena is composed of lead(II)sulfide (PbS) (Molar mass 239.3) and has an average density of 7.46 g/cm^3.

    How many moles of lead(II)silfide are in 5.42 ft^3? of galena?

    How many lead atoms are in 9.15 dm^3 of galena?

    So, I looked up how it says to do it, and it says this-

    moles PbS = (5.42ft^3) x (12 in^3/1 ft^3) x (2.54 cm^3/1in^3) x (7.46 g PbS/1cm^3) x (1mol PbS/239.3 g PbS) = 4790 mol PbS

    How do they get 4790 moles? (5.42 x 12 x 2.54 x7.46) / (239.3) = 5.15 mol? If someone could explain this that would be awesome.

    I'm also not sure how to do the second part.

    Any help is appreciated and will get 10 points if you are correct. (:

    2 AnswersChemistry9 years ago
  • WHO DARES TO POKEMON BATTLE ME!? (5th gen wifi)?

    5th Gen please. (Pokemon black/white)

    No hacked pokemon or hacking please.

    6 v 6 Single battle! No restrictions, No wonder launcher!

    FC: 0003-2897-3807

    Copy down my FC and leave yours and I'll be on wifi waiting.

    And also state whether you want to allow legendary pokemon or not. If you say nothing I WILL ASSUME LEGENDARY POKEMON ARE ALLOWED and I will use them.

    Also my email is Latiosou@yahoo.com if you want to battle later but can't at this moment.

    3 AnswersVideo & Online Games9 years ago
  • WHO DARES TO POKEMON BATTLE ME!? (5th gen wifi)?

    5th Gen please. (Pokemon black/white)

    No hacked pokemon or hacking please.

    6 v 6 Single battle! No restrictions, No wonder launcher!

    FC: 0003-2897-3807

    Copy down my FC and leave yours and I'll be on wifi waiting.

    And also state whether you want to allow legendary pokemon or not. If you say nothing I WILL ASSUME LEGENDARY POKEMON ARE ALLOWED and I will use them.

    Also my email is Latiosou@yahoo.com if you want to battle later but can't at this moment.

    3 AnswersVideo & Online Games9 years ago
  • WHO DARES TO POKEMON BATTLE ME!? (5th gen wifi)?

    5th Gen please. (Pokemon black/white)

    No hacked pokemon or hacking please.

    6 v 6 Single battle! No restrictions, No wonder launcher!

    FC: 0003-2897-3807

    Copy down my FC and leave yours and I'll be on wifi waiting.

    And also state whether you want to allow legendary pokemon or not. If you say nothing I WILL ASSUME LEGENDARY POKEMON ARE ALLOWED and I will use them.

    Also my email is Latiosou@yahoo.com if you want to battle later but can't at this moment.

    Good luck everyone, I'm pretty good so watch out! :D

    1 AnswerVideo & Online Games9 years ago
  • Questions about Diablo 3?

    Question 1:

    Is it a pay per month thing like WoW or SWTOR or is it a 1 time fee like Starcraft? And is it single player or multiplayer? (Or both like starcraft?)

    Question 2:

    Can my computer run it? I can run WoW and League of legends just fine but I can't run SWTOR.

    Specs-

    Windows 7 Home Premium 64-bit (6.1, Build 7600)

    Inspiron N5010

    Intel (R) Core i5 CPU M460 @ 2.53GHz (4 CPUs), ~2.5 GHz

    4096 MB RAM

    DirectX 11

    2 AnswersVideo & Online Games9 years ago
  • Questions about Diablo 3?

    Question 1:

    Is it a pay per month thing like WoW or SWTOR or is it a 1 time fee like Starcraft? And is it single player or multiplayer? (Or both like starcraft?)

    Question 2:

    Can my computer run it? I can run WoW and League of legends just fine but I can't run SWTOR.

    Specs-

    Windows 7 Home Premium 64-bit (6.1, Build 7600)

    Inspiron N5010

    Intel (R) Core i5 CPU M460 @ 2.53GHz (4 CPUs), ~2.5 GHz

    4096 MB RAM

    DirectX 11

    1 AnswerPC9 years ago
  • Physics Question (Work done to move a crate)?

    A 2300 N crate rests on the floor.

    How much work is required to move it at constant speed 4.3 m along the floor against a drag force of 280 N?

    Also, 8686 J and 11064 J are both incorrect. :(

    Any help would be greatly appreciated. (:

    2 AnswersPhysics9 years ago
  • Physics Question (Work done to move a crate)?

    A 2300 N crate rests on the floor.

    How much work is required to move it at constant speed 4.3 m along the floor against a drag force of 280 N?

    How much work is required to move it at constant speed 4.3 m vertically?

    Any help would be greatly appreciated. (:

    3 AnswersEngineering9 years ago
  • Physics homework Question (Uniform Circular Motion)?

    A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), as shown in the figure . The circle formed by the tube has a diameter of about 1.0 km.

    What must be the rotation speed (revolutions per day) if an effect equal to gravity at the surface of the Earth (1.0g) is to be felt?

    w= x rev/day?

    I thought the centripetal force must equal the weight of the object on earth, that is

    mg = m R w^2

    w = sqrt(g/R) = sqrt(9.8/1000) = 0.098994 rads/sec

    revolutions per day = 0.098994 rads/sec * (24*3600 sec/ 1 day) = 8553. revs/day

    8553 revs a day is incorrect however. :(

    ANY help with this problem would be greatly appreciated.

    2 AnswersEngineering9 years ago