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(you have to make a chemical equation first and balanced it) Firstly you have to change to volume unit from ml to L by dividing it with 1000. And then you times it with 0.10 M and what you'll get is the number of moles. Now you have to use the mole ratio from the equation. The mole ratio is the coefficient numbers infront of the substances. If the ratio between 'tris' and HCL is 1:1 then you can use the number of moles that you've got earlier to find the mass. (If the mole ratio is not 1:1, then you have to use this formula: ratio number of 'tris divided by ratio number of HCL and times it by the number of moles you've got earlier). When you get the number of mole, you only need to times that number with the molar mass of 'tris'.
hope this will help
Anonymous
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What is the required mass of "tris" to react with 35 mL of 0.10 M HCl?
Anonymous
2(M) HCl in 100 ml solution =.2 moles of HCl Now from the above equation it is evident that .1 mole CaCO3 reacts with .2 mole HCl So mass of CaCO3=10gm
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Molar Mass Of Tris